Question 38. Based on the correct analysis, which of the following conclusions you think would be truefor the above test of hypothesis.(A) Do not reject H₁. Data do not provide sufficient evidence to conclude that the mean numberof calls per representative per week is more than 40.(B) Do not reject H₁. Data provide sufficient evidence to conclude that the mean number of callsper representative per week is more than 40.(C) Reject H₁. Data do not provide sufficient evidence to conclude that the mean number of callsper representative per week is more than 40.(D) Reject Ho. Data provide sufficient evidence to conclude that the mean number of calls perrepresentative per week is more than 40.(E) None of the aboveQuestions 39-40. The reputations (and hence sales) of many businesses can be severely damaged byshipments of manufactured items that contain a large percentage of defectives. A manufacturer ofAlkaline batteries may want to be reasonably certain that fewer than 5% of its batteries are defective.Suppose that 300 batteries are randomly selected from a very large shipment; each is tested and 10defective batteries are found. Manufacturer wants to know that whether this provide sufficient evidencethat the proportion of the defective in the entire shipment is less than 0.05? To do the above test, aresearcher performed two analyses using Minitab with relevant outputs below.Analysis I Test and Cl for One ProportionNormal approximation method is used for this analysis.Descriptive StatisticsN Event Sample p90% Cl for p300 10 0.033333 (0.016286, 0.050380)Analysis II Test and Cl for One ProportionNormal approximation method is used for this analysis.Descriptive StatisticsN Event Sample p30010 0.033333Z-Value P-Value-1.32 0.18590% Upper Boundfor p Z-Value P-Value0.046615 -1.32 0.093Question 39. To do the above test of hypothesis, which one of the following will be the appropriate nulland alternative hypothesis?(A) H₁: p‡ 0.05 vs H₁: p = 0.05(C) H₁: p0.15 vs H₁: p = 0.15(E) None of the above(B) H₁: p= 0.05 vs H₁: p +0.05(D) H₁: p = 0.05 vs H₁: p

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Question 38. Based on the correct analysis, which of the following conclusions you think would be truefor the above test of hypothesis.(A) Do not reject H₁. Data do not provide sufficient evidence to conclude that the mean numberof calls per representative per week is more than 40.(B) Do not reject H₁. Data provide sufficient evidence to conclude that the mean number of callsper representative per week is more than 40.(C) Reject H₁. Data do not provide sufficient evidence to conclude that the mean number of callsper representative per week is more than 40.(D) Reject Ho. Data provide sufficient evidence to conclude that the mean number of calls perrepresentative per week is more than 40.(E) None of the aboveQuestions 39-40. The reputations (and hence sales) of many businesses can be severely damaged byshipments of manufactured items that contain a large percentage of defectives. A manufacturer ofAlkaline batteries may want to be reasonably certain that fewer than 5% of its batteries are defective.Suppose that 300 batteries are randomly selected from a very large shipment; each is tested and 10defective batteries are found. Manufacturer wants to know that whether this provide sufficient evidencethat the proportion of the defective in the entire shipment is less than 0.05? To do the above test, aresearcher performed two analyses using Minitab with relevant outputs below.Analysis I Test and Cl for One ProportionNormal approximation method is used for this analysis.Descriptive StatisticsN Event Sample p90% Cl for p300 10 0.033333 (0.016286, 0.050380)Analysis II Test and Cl for One ProportionNormal approximation method is used for this analysis.Descriptive StatisticsN Event Sample p30010 0.033333Z-Value P-Value-1.32 0.18590% Upper Boundfor p Z-Value P-Value0.046615 -1.32 0.093Question 39. To do the above test of hypothesis, which one of the following will be the appropriate nulland alternative hypothesis?(A) H₁: p‡ 0.05 vs H₁: p = 0.05(C) H₁: p0.15 vs H₁: p = 0.15(E) None of the above(B) H₁: p= 0.05 vs H₁: p +0.05(D) H₁: p = 0.05 vs H₁: p < 0.05

Accepted Answer

Let p be the population proportion of its batteries that are defective.Given that,Population…

Question 39. To do the above test of hypothesis, which one of the following will be the appropriate null and alternative hypothesis? (A) H₁: p0.05 vs H₁: p = 0.05 (C) Ho: p0.15 vs H₁: p = 0.15 (E) None of the above (B) H₁: p= 0.05 vs H₁: p0.05 (D) H₁: p = 0.05 vs H₁: p < 0.05