Question 42 The correct statements are: If L₁ is reducible to L₂ and L₂ is not in D, then L₁ cannot be in D. If L₁ is reducible to L₂ and L₁ is not in D, then L₂ cannot be in D. If L₁ is reducible to L2 and L₂ is not in SD, then L₁ cannot be in SD. If L₁ is reducible to L₂ and L₁ is not in SD, then L₂ cannot be in SD.
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- Consider the following statement. If n is divisible by 6, then n is divisible by 2 and n is divisible by 3. In (a)–(d) below, select the negation, contrapositive, converse, and inverse for the statement. (Assume that all variables represent fixed quantities or entities, as appropriate.) (a) Negation n is divisible by 6 and either n is not divisible by 2 or n is not divisible by 3.If n is not divisible by 2 or n is not divisible by 3, then n is not divisible by 6. If n is divisible by 2 and n is divisible by 3, then n is divisible by 6.If n is not divisible by 6, then n is not divisible by 2 or n is not divisible by 3.If n is not divisible by 6, then n is divisible by 2 and n is divisible by 3. (b) Contrapositive n is divisible by 6 and either n is not divisible by 2 or n is not divisible by 3.If n is not divisible by 2 or n is not divisible by 3, then n is not divisible by 6. If n is divisible by 2 and n is divisible by 3, then n is divisible by 6.If n is not divisible by 6, then…Similarly to question in number 2, using x = 4 ; and y = 2 ; and operator = ' * '. What is the final value of x?1. Suppose we are in the middle of a proof and our current goal is: S(c)→(∀d)(M(d)→R(d,c)) Suppose the next line of the proof is "Assume S(c)." Which of the following does the goal change to? (∀d)(M(d)→R(d,c)) S(c)→(∀d)(M(d)→R(d,c)) M(d)→R(d,c) S(c)→M(c) 2. Suppose we are in the middle of a proof and our current goal is: (∀d)(R(d,c)→R(c,d)) Suppose the next line of the proof is "Let d be an arbitrary (whatever its type is)." Which of the following does the goal change to? Group of answer choices R(d,c)→R(c,d) (∀d)(R(d,c)→R(c,d)) R(d,c) R(c,d)
- "Equatable and Comparable" in the Swift Programming: The Big Nerd Ranch Guide (2nd Ed.) e-book: Point’s current conformance to Comparable yields some confusing results. let c = Point(x: 3, y: 4) let d = Point(x: 2, y: 5) let cGreaterThanD = (c > d) // false let cLessThanD = (c < d) // false let cEqualToD = (c == d) // false As the above example demonstrates, the trouble arises in comparing two points when one point’s x and y properties are not both larger than the other point’s. In actuality, it is not reasonable to compare two points in this manner. Fix this problem by changing Point’s conformance to Comparable. Calculate each point’s Euclidean distance from the origin instead of comparing x and y values. This implementation should return true for a < b when a is closer to the origin than b. Use the formula shown in below Figure 25.1 to calculate a point’s Euclidean distance. Figure 25.1 Euclidean distance Euclidean distanceShow if the statements are true or false and provide a brief explaination as to why. If A ∈ B and B ∈ C, is it true that A ∈ C? If A ∈ B and B ∈ C, then is it impossible that A ∈ C? If A ∈ B, then is it impossible for A to be contained in B?Answer the following: This problem exercises the basic concepts of game playing, using tic-tac-toe (noughts and crosses) as an example. We define Xn as the number of rows, columns, or diagonals with exactly n X’s and no O’s. Similarly, On is the number of rows, columns, or diagonals with just n O’s. The utility function assigns +1 to any position with X3=1 and −1 to any position with O3=1. All other terminal positions have utility 0. For nonterminal positions, we use a linear evaluation function defined as Eval(s)=3X2(s)+X1(s)−(3O2(s)+O1(s)). a. Show the whole game tree starting from an empty board down to depth 2 (i.e., one X and one O on the board), taking symmetry into account. b. Mark on your tree the evaluations of all the positions at depth 2. c .Using the minimax algorithm, mark on your tree the backed-up values for the positions at depths 1 and 0, and use those values to choose the best starting move. Provide original solutions including original diagram for part a!
- Answer the following: This problem exercises the basic concepts of game playing, using tic-tac-toe (noughts and crosses) as an example. We define Xn as the number of rows, columns, or diagonals with exactly n X’s and no O’s. Similarly, On is the number of rows, columns, or diagonals with just n O’s. The utility function assigns +1 to any position with X3=1 and −1 to any position with O3=1. All other terminal positions have utility 0. For nonterminal positions, we use a linear evaluation function defined as Eval(s)=3X2(s)+X1(s)−(3O2(s)+O1(s)). a. Show the whole game tree starting from an empty board down to depth 2 (i.e., one X and one O on the board), taking symmetry into account. b. Mark on your tree the evaluations of all the positions at depth 2. c .Using the minimax algorithm, mark on your tree the backed-up values for the positions at depths 1 and 0, and use those values to choose the best starting move. Provide original solution!A staff number of a BigHit company is composed of 2 non-vowels uppercase alphabets and 3 digit mumbers. i How many staffnumbers can be generated if the company requested to start the first letter with J and the 3 digit numbers (repetition not allowed)? ii. How many ways the staff number can be formed if it has any consonants and odd numbers with repetition allowed?What is the synonym of the underlined word below? The great error in Rip's composition was an insuperable aversion to all kinds of profitable labor,a) O a petty quarrel or argumentb) O Incapable of being overcomec) O troublesome or annoyingd) O a strong feeling of perfectnesse) O a strong feeling of dislike
- Three persons P1, P2, and P3 were invited by their friend F to make some smørbrød (sandwich made of bread, eggs, and tomato) together. To make a portion of smørbrød, three ingredients are needed: a slice of bread, a slice of tomato, and a slice of an egg. Each of these persons P1, P2, P3 has only one type of each of the ingredients: person P1 has slices of bread person P2 has slices of tomato; person P3 has slices of egg. We assume that persons P1, P2, and P3 each has an unlimited supply of these ingredients (i.e., slices of bread, slices of tomato, slices of egg), respectively. Their friend F, who invited them, also has an unlimited supply of all the ingredients. Here is what happens: the host F puts two random ingredients on the table. Then the invited person who has the third ingredient picks up these other two ingredients, and makes the smørbrød (i.e., takes a slice of bread, puts on it a slice of tomato, and puts on top a slice of egg), and then eats the smørbrød. The host of…I need help figuring out the following HW question41. Which of the following statements is not true for the deadlock prevention and deadlock avoidance schemes? a. Deadlock avoidance is less restrictive than deadlock prevention. b. In deadlock prevention, the request for resources is always granted, if the resulting state is safe. c. It is the priority to have the knowledge of resource requirements for deadlock avoidance. d. In deadlock avoidance, the request for resources is always granted, if the resulting state is safe.