Question 6 of 6 < View Policies - / 10 Current Attempt in Progress The figure shows the finishing position of a body builder's arm who is performing a standing lateral raise with a 5.00-kg dumbbell. This is an excellent exercise that isolates the lateral deltoid muscle. The weight of the arm itself is 42.5 N, and it acts at point A in the figure. Given the information shown, and the fact that 0 = 9.74°, (a) find the magnitude of the tension force in the deltoid (d) and (b) the normal force from the shoulder joint (Fs) acting on the humerus bone that holds the arm in this equilibrium position. 5 kg 0.075 m W arm 0.250 m Wa (a) Number i Units N (b) Number i Units 0.510 m

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Author:Raymond A. Serway, John W. Jewett
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Chapter1: Physics And Measurement
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Current Attempt in Progress
The figure shows the finishing position of a body builder's arm who is performing a standing lateral raise with a 5.00-kg dumbbell. This
is an excellent exercise that isolates the lateral deltoid muscle. The weight of the arm itself is 42.5 N, and it acts at point A in the figure.
Given the information shown, and the fact that 0 = 9.74°, (a) find the magnitude of the tension force in the deltoid (d) and (b) the
normal force from the shoulder joint (Fs) acting on the humerus bone that holds the arm in this equilibrium position.
5 kg
0.075 m
W
arm
0.250 m
Wa
(a) Number i
Units
N
(b) Number
i
Units
0.510 m
Transcribed Image Text:Question 6 of 6 < View Policies - / 10 Current Attempt in Progress The figure shows the finishing position of a body builder's arm who is performing a standing lateral raise with a 5.00-kg dumbbell. This is an excellent exercise that isolates the lateral deltoid muscle. The weight of the arm itself is 42.5 N, and it acts at point A in the figure. Given the information shown, and the fact that 0 = 9.74°, (a) find the magnitude of the tension force in the deltoid (d) and (b) the normal force from the shoulder joint (Fs) acting on the humerus bone that holds the arm in this equilibrium position. 5 kg 0.075 m W arm 0.250 m Wa (a) Number i Units N (b) Number i Units 0.510 m
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