QUESTION 8 8. This is the first of four questions. Starting from 0.0010 M N205. 10.0 M NO2 and 10.0 M O2 what is the value of AGO at 298 K? 2 N2O5(9) 4 NO2(g) + 02 (9) = Substance AG°f (kJ/mol) N2O5 +115 NO2 +51 Report your answer in kJ with as a whole number (the ones place), but do not write the units. Include a - if applicable. 7 QUESTION 9 9. This is the second of four questions. Starting from 0.0010 M N2O5, 10.0 M NO2 and 10.0 M O2 what is the value of AG at 298 K? 2 N2O5(9) O2 (g) = 4 NO2(g) +

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter3: Chemical Reactions
Section: Chapter Questions
Problem 125QRT: A student set up an experiment for six different trials of the reaction between 1.00-M aqueous...
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QUESTION 8
8. This is the first of four questions. Starting from 0.0010 M N2O5, 10.0 M NO2 and 10.0 M O2 what is the value of AGO at 298 K?
2 N₂05(9)
=
4 NO2(g) +
02 (9)
Substance
AG°f (kJ/mol)
N₂O5
+115
NO2
+51
Report your answer in kJ with as a whole number (the ones place), but do not write the units. Include a
if applicable.
1
QUESTION 9
9. This is the second of four questions. Starting from 0.0010 M N2O5, 10.0 M NO2 and 10.0 M O2 what is the value of AG at 298 K?
2 N₂05(9) =
4 NO2(g) + O2 (g)
Substance
N₂0
AG°f (kJ/mol)
Transcribed Image Text:← fordham.blackboard.com/webapps/assessment/take/launch.jsp?course_assessment_id=_97 Question Completion Status: OK <1 OK > 1 OK<0 OK=0 O K=1 QUESTION 8 8. This is the first of four questions. Starting from 0.0010 M N2O5, 10.0 M NO2 and 10.0 M O2 what is the value of AGO at 298 K? 2 N₂05(9) = 4 NO2(g) + 02 (9) Substance AG°f (kJ/mol) N₂O5 +115 NO2 +51 Report your answer in kJ with as a whole number (the ones place), but do not write the units. Include a if applicable. 1 QUESTION 9 9. This is the second of four questions. Starting from 0.0010 M N2O5, 10.0 M NO2 and 10.0 M O2 what is the value of AG at 298 K? 2 N₂05(9) = 4 NO2(g) + O2 (g) Substance N₂0 AG°f (kJ/mol)
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