Question A current of 5.19 A is passed through a Pb(NO3)2 solution for 1.20 h. How much lead is plated out of the solution?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter18: Electrochemistry
Section: Chapter Questions
Problem 128AE: It took 150. s for a current of 1.25 A to plate out 0.109 g of a metal from a solution containing...
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I have a question. Under the periodic table the charge for Pb is 4+. Why does the equation say 2+. Just trying to understand so I don't mess up on tests. 

First we calculate moles of election
It
F
current x time
Moles of electron
since,
2
=
5.19 A
рьта
moles of Pb(s) =
+ 9 é
Mass of Pb(s)
c/s) (1.90 hrs.
0.232 moler
=
=
:
=
farraday constant
96485
=
24.03
X
Pb(s)
0.232 mol. ex
Go min
1 hr.
ร
рь
0.116 mol Pb
0.116 Mol pb) (207.2 g/mol)
60 second
I min
I mol Pb
& molé
Transcribed Image Text:First we calculate moles of election It F current x time Moles of electron since, 2 = 5.19 A рьта moles of Pb(s) = + 9 é Mass of Pb(s) c/s) (1.90 hrs. 0.232 moler = = : = farraday constant 96485 = 24.03 X Pb(s) 0.232 mol. ex Go min 1 hr. ร рь 0.116 mol Pb 0.116 Mol pb) (207.2 g/mol) 60 second I min I mol Pb & molé
Question
A current of 5.19 A is passed through a Pb(NO3)2 solution for 1.20 h. How much lead is plated out of the solution?
Transcribed Image Text:Question A current of 5.19 A is passed through a Pb(NO3)2 solution for 1.20 h. How much lead is plated out of the solution?
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