Question: Could you please explain the bolded part with more detail? Specifically the bolded and underlined part. Where did the (5t*0.5) come from? What formula for the Flux in B was used?

University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
Publisher:OpenStax
Chapter13: Electromagnetic Induction
Section: Chapter Questions
Problem 69AP: The conducting rod shown in the accompanying figure moves along parallel metal rails that are 25-cm...
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For the problem in the picture, I recieved the following answer:

Introduction

Electromagnetic Induction or Induction is a process in which a conductor is put in a particular position and magnetic field keeps varying or magnetic field is stationary and a conductor is moving. This produces a Voltage or EMF (Electromotive Force) across the electrical conductor. 

So we can say that:

The induction of an electromotive force by the motion of a conductor across a magnetic field or by a change in magnetic flux in a magnetic field is called ‘Electromagnetic Induction’.

 

Calculation and concepts

a) Given that the current flows in clockwise direction in the circuit. So the current in the rod is in -y direction.

Force acting on the rod is in x direction.

Force on a current carrying wire in a magnetic field is given as:

F= i ( dl × B)

i = current in the wire

dl = small length element

B = magnetic field

Since dl and B are perpendicular, we get

F= Bil and direction of magnetic using right hand rule we get is inside the page that is -z direction.

b) Induced potential due to time varying magnetic field is given as

E = -d(flux) /dt =d(5t * 0.5)*B /dt = 2.5B Volts

E = iR

i = 2.5 B/2 

Force = BiL 

10 = B* (2.5 B/2)*0.5 

B^2 = 80/5 = 16 

B = 4 Tesla

c) we know

F = i (dl × B)

Since direction of F is reversed direction of current also gets reversed. That is now the current will flow in y direction. 

Question: Could you please explain the bolded part with more detail? Specifically the bolded and underlined part. Where did the (5t*0.5) come from? What formula for the Flux in B was used?

A metal bar slides to the right under the action of an external force Fext, on a pair of parallel rails, without
friction and conductors placed in a horizontal plane. The rails are separated by a distance L and are connected
by a resistor R. We will assume that the resistance of the rails and the rod is negligible. The system is placed in
a region with a uniform magnetic field B perpendicular to the page, and the induced current in the rod is
observed to be directed down the page.
a) If the rod is to slide with constant speed to the right, what must be the direction of the magnetic field B?
b) If Fext = 10 N, R= 2ohm, L= 50 cm and v = 5 m/s, calculate the magnitude of the magnetic field to be
applied.
c) If now the external force is applied to the left and the rod moves to the left with the same speed,
maintaining the same magnitude and direction of the magnetic field, in which direction does the induced
current in the rod now go?
L
R
Fat
Transcribed Image Text:A metal bar slides to the right under the action of an external force Fext, on a pair of parallel rails, without friction and conductors placed in a horizontal plane. The rails are separated by a distance L and are connected by a resistor R. We will assume that the resistance of the rails and the rod is negligible. The system is placed in a region with a uniform magnetic field B perpendicular to the page, and the induced current in the rod is observed to be directed down the page. a) If the rod is to slide with constant speed to the right, what must be the direction of the magnetic field B? b) If Fext = 10 N, R= 2ohm, L= 50 cm and v = 5 m/s, calculate the magnitude of the magnetic field to be applied. c) If now the external force is applied to the left and the rod moves to the left with the same speed, maintaining the same magnitude and direction of the magnetic field, in which direction does the induced current in the rod now go? L R Fat
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