Question There are two lines through the point (−1, 3) that are tangent to the curve x^2 + 4y^2 − 4x − 8y + 3 = 0. Find the equation of these two lines.  Answers tangent 1: x + 4 = 11 tangent 2: 11x + 4 = 1 Show me to get the answers by differentiation.

Q: why did we put x = 1? the final answer i got is 49/e, please double-check

A: After double checking the detailed solution is given below

Q: answer item 2

A: Topic:- limit

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A: For second question reupload it according to bartleby guidelines i can do only one question

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