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RCВwwRwwR(awwR Aww

Question

The current through each resistor in  if each resistance R = 4.25 kΩ and V = 14.0 V . What is the through resistor a,b,c,d,e,f, and g?

R
C
В
ww
R
ww
R
(a
ww
R A
ww
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R C В ww R ww R (a ww R A ww

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check_circleAnswer
Step 1

Given that the value of all the resistors is equal and has the value R=4.25kΩ.

The circuit is shown below.

Rf
Rd
www
V
Rp
www
Ra
A
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Rf Rd www V Rp www Ra A

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Step 2

The resistor Ra and Rb are connected in series , the equivalent Resistance is given by

ab
=4.25k 4.25k
8.5k2
The resistor Ris parallel connection with Ra,their equivalent resi stance is given by
1
1
1
_
R
R
abe
ab
1
1
=
8.5k 4.25k
Rte 2.83k
abe
The resistor Ris in series connection with R^e, their equivalent resistance is given by
abe
+
abe
abed
-2.83k4.25k
= 7.08k2
The resistor Ris in parallel connection with Red their equivalent resistance is given by
1
1
1
=
abede
abed
1
1
7.08k 4.25k
abede =2.65KO
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ab =4.25k 4.25k 8.5k2 The resistor Ris parallel connection with Ra,their equivalent resi stance is given by 1 1 1 _ R R abe ab 1 1 = 8.5k 4.25k Rte 2.83k abe The resistor Ris in series connection with R^e, their equivalent resistance is given by abe + abe abed -2.83k4.25k = 7.08k2 The resistor Ris in parallel connection with Red their equivalent resistance is given by 1 1 1 = abede abed 1 1 7.08k 4.25k abede =2.65KO

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Step 3

The equivalent resistor Rabcde  is in series connection with the resistor Rf , and current through both these...

V
If
abede
14.0 V
(4.25+2.65)k2
-2.02mA
The current through resistance R is
abed
1.=RedR;
7.08k
= (2.02mA)o8k2+4.25k2
1.26mA
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V If abede 14.0 V (4.25+2.65)k2 -2.02mA The current through resistance R is abed 1.=RedR; 7.08k = (2.02mA)o8k2+4.25k2 1.26mA

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