An exam consists of 50 multiple-choice questions. Based on how much you studied, for any given question, you think you have a probability of p = 0.7 of getting the correct answer. Consider the sampling distribution of sample proportion of the 50 questions on which you get the correct answer.If truly p = 0.7, would it be very surprising if you got correct answers on only 60% of the questions? Justify your answer by using the normal distribution to approximate the probability of a sample proportion of 0.6 or less. The correct answer to this question is 0.0618. However, when I calculate the answer I keep getting 0.0615 using normalcdf(-1099,1.543,0,1). I have included a photo of my calculations. Please share with me what I am doing wrong when calculating this problem. Thank you! (р - Е(Ф) р- Е(р)p - E(p)P(p < 0.60) = P0.6-0.7= P(Z<0.0648,= P(Z <-1.543)= Z < 1.543= 1- 0.9385= 0.0615

According the provided information, the sample size, n is 50 and the probability, p is 0.7. The mean…

Answered: (р - Е(Ф) р- Е(р) p - E(p) P(p < 0.60)…

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter6: The Trigonometric Functions

Section6.4: Values Of The Trigonometric Functions

Problem 21E

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An exam consists of 50 multiple-choice questions. Based on how much you studied, for any given question, you think you have a probability of p = 0.7 of getting the correct answer. Consider the sampling distribution of sample proportion of the 50 questions on which you get the correct answer.

- If truly p = 0.7, would it be very surprising if you got correct answers on only 60% of the questions? Justify your answer by using the normal distribution to approximate the probability of a sample proportion of 0.6 or less.

The correct answer to this question is 0.0618. However, when I calculate the answer I keep getting 0.0615 using normalcdf(-10⁹⁹,1.543,0,1). I have included a photo of my calculations. Please share with me what I am doing wrong when calculating this problem. Thank you!

(р - Е(Ф) р- Е(р)
p - E(p)
P(p < 0.60) = P
0.6-0.7
= P(Z<
0.0648,
= P(Z <-1.543)
= Z < 1.543
= 1- 0.9385
= 0.0615

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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(р - Е(Ф) р- Е(р) p - E(p) P(p < 0.60) = P 0.6-0.7 = P(Z< 0.0648, = P(Z <-1.543) = Z < 1.543 = 1- 0.9385 = 0.0615