r=1 m r =2 m 1 r 3 m Figure 6.11 Sound Intensity Anillustration of the inverse-square law for a point source ( ox 1/r. Note that when the distance from the source doubles-for example, from 1 m to 2 m-the intensity decreases to one-fourth its former value because the sound must pass through four times the area.

College Physics
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Chapter17: Physics Of Hearing
Section: Chapter Questions
Problem 68PE: (a) Find the intensity in watts per meter squared of a 60.0Hz sound having a loudness of 60 phons....
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Referring to Fig. 6.11, indicate over how many squares the sound waves would spread for r=5m. The sound intensity would decrease to what fraction in value?

r=1 m
r =2 m
1
r 3 m
Figure 6.11 Sound Intensity Anillustration of the inverse-square law for a point source
( ox 1/r. Note that when the distance from the source doubles-for example, from 1 m to
2 m-the intensity decreases to one-fourth its former value because the sound must pass
through four times the area.
Transcribed Image Text:r=1 m r =2 m 1 r 3 m Figure 6.11 Sound Intensity Anillustration of the inverse-square law for a point source ( ox 1/r. Note that when the distance from the source doubles-for example, from 1 m to 2 m-the intensity decreases to one-fourth its former value because the sound must pass through four times the area.
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