RB=8kQ VIN igure 2(a) 10VQ R=2ΚΩ VOUT B Figure 2(b) R₁=23kQ R=2kQ C₁ 10V VIN R₂=3kQ RE=2000 C₂ Figure 3(a) VBE -O VOUT

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Figures 2(a) and 2(b) show a simple transistor amplifier
and a simplified large signal model of a transistor,
respectively.


(i) Assuming the transistor is in the active region,
redraw the circuit in Figure 1(a) by using the
simplified large signal model (Figure 1b) in place
of the transistor, and derive an expression
relating VOUT to VIN.
[4 marks]

(ii) Based on the expression in a(i), sketch the
voltage transfer characteristics curve, i.e., VOUT
vs VIN. Comment on the limitations of the
simplified large signal model.
[3 marks]


(iii) Assuming VBE(on) = 0.7V and VCE(saturation) = 0.2V,
redraw your sketch to include its cut-off, active
and saturation regions. Mark on this sketch a
suitable quiescent operating point for the circuit
and explain your reasoning.
[3 marks]

RB=8kQ
VIN
igure 2(a)
10VQ
R=2ΚΩ
VOUT
B
Figure 2(b)
R₁=23kQ
R=2kQ
C₁
10V
VIN
R₂=3kQ
RE=2000
C₂
Figure 3(a)
VBE
-O VOUT
Transcribed Image Text:RB=8kQ VIN igure 2(a) 10VQ R=2ΚΩ VOUT B Figure 2(b) R₁=23kQ R=2kQ C₁ 10V VIN R₂=3kQ RE=2000 C₂ Figure 3(a) VBE -O VOUT
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