re, an insulated rigid tank is divided into two equal parts by a partition. Initially, one part contains an indeal gas, and the other part is evacuated. The partition is then removed, and the gas expands into the entire tank. At the initial state, the mass of the gas is m= 4.00kg, initial pressure is p1 = 600.00 kPa, initial temperature is T1 = 300.00 K. The gas constant is R = 0.2870 kJ/(kg·K). (The internal energy can be determined by the equation ΔU=m·cv·(T2-T1), where cv =  0.7180 kJ/(kg·K) is the specific heat at the constant volume.)  Calculate the final state temperature pressur

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Shown in the figure, an insulated rigid tank is divided into two equal parts by a partition. Initially, one part contains an indeal gas, and the other part is evacuated. The partition is then removed, and the gas expands into the entire tank. At the initial state, the mass of the gas is m= 4.00kg, initial pressure is p1 = 600.00 kPa, initial temperature is T1 = 300.00 K. The gas constant is R = 0.2870 kJ/(kg·K). (The internal energy can be determined by the equation ΔU=m·cv·(T2-T1), where c=  0.7180 kJ/(kg·K) is the specific heat at the constant volume.) 

Calculate the final state temperature pressure p2.__________ (kPa)



 

Shown in the figure, an insulated rigid tank is divided into two equal parts by a partition. Initially, one part contains an indeal gas, and the other part is
evacuated. The partition is then removed, and the gas expands into the entire tank. At the initial state, the mass of the gas is m= 4.00kg, initial pressure
is p1 = 600.00 kPa, initial temperature is T1 = 300.00 K. The gas constant is R = 0.2870 kJ/(kg-K). (The internal energy can be determined by the
equation AU=m-cy (T₂-T1), where cy= 0.7180 kJ/(kg-K) is the specific heat at the constant volume.)
Calculate the final state temperature pressure p2.,
Ideal gas
T1
P1
V1
m
State 1
Evacuated
(kPa)
Ideal gas
T2=?
P2=?
V2=2V1
State 2
Transcribed Image Text:Shown in the figure, an insulated rigid tank is divided into two equal parts by a partition. Initially, one part contains an indeal gas, and the other part is evacuated. The partition is then removed, and the gas expands into the entire tank. At the initial state, the mass of the gas is m= 4.00kg, initial pressure is p1 = 600.00 kPa, initial temperature is T1 = 300.00 K. The gas constant is R = 0.2870 kJ/(kg-K). (The internal energy can be determined by the equation AU=m-cy (T₂-T1), where cy= 0.7180 kJ/(kg-K) is the specific heat at the constant volume.) Calculate the final state temperature pressure p2., Ideal gas T1 P1 V1 m State 1 Evacuated (kPa) Ideal gas T2=? P2=? V2=2V1 State 2
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