Read in the tree inventory file, created in Lab 3W, and show a count of the number of times a specific species of tree occurs in the file. Once you unscramble the program, display the number of oak trees. Unscramble the code below so the output is "there are 3 oak trees": from BrowserFile import open import csv for y in r: k = 0 with open("treeinventory.csv", "r", newline = ") as f: fort in y: tree input("enter tree type to get a count") k = k + 1 ift== tree: print("there are",k, tree,'trees') r = csv.reader (f)
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- Write a program that reads a text file and creates an alphabetical index of words and in which lines of this original example. The file name is given as an argument to main (). Ignore the small-capital (all lowercase: k,l,p) and punctuation. Solve with ternary tree using the TST.java class (https://algs4.cs.princeton.edu/52trie/TST.java.html). An execution snapshot is then given. For the file: It was the best of times, it was the worst of times, it was the age of wisdom, it was the age of foolishness It will appear Index of file: exercise.txt age 3-4 best 1 foolishness 4 it 1-2-3-4 of 1-2-3-4 the 1-2-3-4 times 1-2 was 1-2-3-4 wisdom 3 worst 2Can you please help update this? //A6Utilities.java import java.io.IOException;import java.nio.file.Files;import java.nio.file.Paths;import java.security.SecureRandom;import java.util.List;import java.util.TreeMap;import java.util.function.Function;import java.util.stream.Collectors;public class A6Utilities {/*** Returns the corresponding letter grade. Don't modify this method, simply use it when converting single* grades to their equivalent letter grade** @param grade the integer grade to convert* @return the letter grade equivalent to the integer grade*/private static char letterGrade(final int grade) {if (grade < 0) return '?';else if (grade < 60) return 'F';else if (grade < 70) return 'D';else if (grade < 80) return 'C';else if (grade < 90) return 'B';else if (grade <= 100) return 'A';else return '?';}/*** The method uses Java Streams only. Don't use any looping structures, conditional statements are OK (IF, TERNARY, SWITCH)* <p>* Generates a list of secure…Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print: 7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = courseGrades.length - 1. import java.util.Scanner; public class CourseGradePrinter {public static void main (String [ ] args) {Scanner scnr = new Scanner(System.in);final int NUM_VALS = 4;int [ ] courseGrades = new int[NUM_VALS];int i; for (i = 0; i < courseGrades.length; ++i) {courseGrades[i] = scnr.nextInt();} /* Your solution goes here */ }}
- PYTHON: Can you please help me to modify this code in a way that it prints out the same output as the image below. class Node:def __init__(self, key):self.left = Noneself.right = Noneself.val = key# this is the function for Inorderdef printInorder(root):if root:# here calling the left childprintInorder(root.left)# here printing the node dataprint(root.val, end=" "),# here calling the right childprintInorder(root.right)# this is the Preorder methoddef printPreorder(root):if root:# here printing the node dataprint(root.val, end=" "),# here calling the left childprintPreorder(root.left)# here calling the right childprintPreorder(root.right)# thsi is the postorder methoddef printPostorder(root):if root:# here calling the left childprintPostorder(root.left)# here calling the right childprintPostorder(root.right)# here printing the node dataprint(root.val, end=" "),# this is the main functionif __name__ == "__main__":root = Node('G')root.left = Node('D')root.right = Node('B')root.left.left…THE QUESTION IS ATTACHED: PLEASE AVOID USING import java.util.ArrayList; import java.util.HashMap; import java.util.Map; BECAUSE I HAVEN'T STUDIED THEM YET, YOU CAN USE 1D AND 2D ARRAYS. YOU ARE FREE TO USE import java.io.File; import java.io.FileNotFoundException; import java.io.FileWriter; import java.io.IOException; EFFECTIVELY USE LOOPS AND CONTROL STATEMENTS. ALSO TRY AND CATCH. TXT. FILE IS INCLUDED BELOW: MOVIE NAME, MOVIE YEAR, RATING AND GENRE. The Martian2015Adventure8.0Murder on the Orient Express2017Crime6.5X-Men: First Class2011Action7.7X-Men: Days of Future Past2014Action7.9This Means War2012Action6.3Godzilla vs. Kong2021Adventure6.5Black Widow2021Action7.5Zack Snyder's Justice League2021Action8.1The Ten Commandments1956Drama7.9The Father2020Drama8.3Nobody2021Crime7.5Promising Young Woman2020Crime7.5What Lies Below2020Horror4.4Shrine2021Horror5.1Bram Stoker's Dracula1992Horror7.4from typing import TextIOdef allergy_checker(shopping_lists: TextIO, clean_shopping_lists: TextIO, allergies: list[str]) -> None: '''shopping_lists is a file open for reading that has at least one food name on everynon-blank line. Food names are separated by a space.Each line in shopping_lists ends with a newline character.clean_shopping_lists is a file open for writing.allergies is a list of one-word food names.Copy lines from shopping_lists to clean_shopping_lists.For each food name that is in the allergies list, replaces it with 'REMOVED'.If a blank line in shopping_lists is reached, stop reading the file.'''shopping_lists = open(shopping_lists) # Line 1clean_shopping_lists = open(clean_shopping_lists, 'w') # Line 2line = shopping_lists.readline() # Line 3while line.strip(): # Line 4line = shopping_lists.readline()…
- THE QUESTION IS ATTACHED: PLEASE AVOID USING import java.util.ArrayList; import java.util.HashMap; import java.util.Map; BECAUSE I HAVEN'T STUDIED THEM YET, YOU CAN USE 1D AND 2D ARRAYS. YOU ARE FREE TO USE import java.io.File; import java.io.FileNotFoundException; import java.io.FileWriter; import java.io.IOException; EFFECTIVELY USE LOOPS AND CONTROL STATEMENTS. TXT. FILE IS INCLUDED BELOW: MOVIE NAME, MOVIE YEAR, RATING AND GENRE. The Martian2015Adventure8.0Murder on the Orient Express2017Crime6.5X-Men: First Class2011Action7.7X-Men: Days of Future Past2014Action7.9This Means War2012Action6.3Godzilla vs. Kong2021Adventure6.5Black Widow2021Action7.5Zack Snyder's Justice League2021Action8.1The Ten Commandments1956Drama7.9The Father2020Drama8.3Nobody2021Crime7.5Promising Young Woman2020Crime7.5What Lies Below2020Horror4.4Shrine2021Horror5.1Bram Stoker's Dracula1992Horror7.4You will also have to write Student Tests that test the following in the provided file.i. Adding element(s).ii. Get elements at index – (1) with a valid index and (2) with an invalid indexiii. Test equality of two StringArrayLists (of size 0, 2)iv. Test if a StringArrayList contains a String (test both true and false cases)v.Test removing a String from a StringArrayList.Consider a text file of names, with one name per line, that has been compiled from several different sources. A sample is shown below:Brooke TroutDinah SoarsJed DyeBrooke TroutJed DyePaige TurnerThere are duplicate names in the file. We would like to generate aninvitation list but don’t want to send multiple invitations to the sameperson. Write a program that eliminates the duplicate names by usinga HashSet. Read each name from the file, add it to the HashSet, andthen output all names in the HashSet to generate the invitation listwithout duplicates
- please update generateRandoms, letterToGrades, sumBetween, countCharacters //A6Utilities.java import java.io.IOException;import java.nio.file.Files;import java.nio.file.Paths;import java.security.SecureRandom;import java.util.List;import java.util.TreeMap;import java.util.function.Function;import java.util.stream.Collectors;public class A6Utilities {/*** Returns the corresponding letter grade. Don't modify this method, simply use it when converting single* grades to their equivalent letter grade** @param grade the integer grade to convert* @return the letter grade equivalent to the integer grade*/private static char letterGrade(final int grade) {if (grade < 0) return '?';else if (grade < 60) return 'F';else if (grade < 70) return 'D';else if (grade < 80) return 'C';else if (grade < 90) return 'B';else if (grade <= 100) return 'A';else return '?';}/*** The method uses Java Streams only. Don't use any looping structures, conditional statements are OK (IF, TERNARY,…Stack CreateStack(S) push (S, 10) push (S, 15) push (S, 20) x = top (S) push (S, x + 5) x = pop (S) + top (S) push (S, x – pop (S)) push (S, pop (pop (S))) push (S, x – top (S)) push (S, push(S, x) – top (S)) After executing the given codes above, answer the questions and explain. ThanksHelp debugging code written in python to get the output from the attached image, def main(): # set the initial month and declarationmonth = 1old_adults = 0old_babies = 0adults = 1 # initial adult pairbabies = 0 # initial babies pairtotal = 0 # storing the total number of rabbit pairsmax = 500 # maximum number of rabbit pairs that can be accomodated# output filefile = open("rabbit_sim.txt",'w')# header of output filefile.write("# Table of rabbit pairs\n")file.write("Month, Adults, Babies, Total\n")# calculate the total number of rabbit pairs for the monthtotal = adults+babies# loop that continues till total rabbit pairs < maxwhile total < max:# output the counts to filefile.write(str(month)+", "+str(adults)+", "+str(babies)+", "+str(total)+"\n")month += 1 # increment the month# set the old_adults and old_babies to current adults and babiesold_adults = adultsold_babies = babies# calculate the adults and babies for next monthbabies = adultsadults = old_adults + old_babiestotal =…