help pleasee 7 to 12 I READING WRONG METER MARKSADDING OR DROPPING A FULL TAPE LENGTHERRORERRORMISTAKEMISTAKEL IMPERFECT ALIGNMENT OF TAPE6 IMPERFECT ALIGNMENT OF TAPEERRORO MISTAKEERRORMISTAKE5 IMPERFECTION OF OBSERVATIONERROR* TAPE NOT STRETCH STRAIGHTMISTAKEERRORMISTAKEA ADDING A CM., USUALLY IN MEASURING THE FRACTIONAL PART OF TAPEAT THE END OF THE LINEERRORVARIATIONS IN TENSIONMISTAKEERROR9 RECORDING NUMBERS INCORRECTLY (EXAMPLE 78 IS READ AS 87)O MISTAKEERRORMISTAKE1o TAPE NOT HORIZONTALO ERRORMISTAKEI| VARIATIONS IN TEMPERATUREERRORO MISTAKEL TAPE NOT STANDARD LENGTHERRORO MISTAKE

7 - Error Tape is not stretched straight due to its weight which causes sag in the tape . This is…

READING WRONG METER MARK (ADDING OR DROPPING A FULL TAPE LENGTH O ERROR ERROR O MISTAKE MISTAKE IMPERFECT ALIGNMENT OF TAPE 6 IMPERFECT ALIGNMENT OF TAPE ERROR O MISTAKE O ERROR MISTAKE IMPERFECTION OF OBSERVATION O ERROR * TAPE NOT STRETCH STRAIGHT O MISTAKE ERROR MISTAKE ADDING A CM., USUALLY IN MEASURING THE FRACTIONAL PART OF TAPE AT THE END OF THE LINE ERROR VARIATIONS IN TENSION O MISTAKE O ERROR 4 RECORDING NUMBERS INCORRECTLY (EXAMPLE 78 IS READ AS 87) MISTAKE O ERROR O MISTAKE 16TAPE NOT HORIZONTAL O ERROR O MISTAKE | VARIATIONS IN TEMPERATURE O ERROR O MISTAKE 12 TAPE NOT STANDARD LENGTH O ERROR O MISTAKE O O

READING WRONG METER MARK (ADDING OR DROPPING A FULL TAPE LENGTH O ERROR ERROR O MISTAKE MISTAKE IMPERFECT ALIGNMENT OF TAPE 6 IMPERFECT ALIGNMENT OF TAPE ERROR O MISTAKE O ERROR MISTAKE IMPERFECTION OF OBSERVATION O ERROR * TAPE NOT STRETCH STRAIGHT O MISTAKE ERROR MISTAKE ADDING A CM., USUALLY IN MEASURING THE FRACTIONAL PART OF TAPE AT THE END OF THE LINE ERROR VARIATIONS IN TENSION O MISTAKE O ERROR 4 RECORDING NUMBERS INCORRECTLY (EXAMPLE 78 IS READ AS 87) MISTAKE O ERROR O MISTAKE 16TAPE NOT HORIZONTAL O ERROR O MISTAKE | VARIATIONS IN TEMPERATURE O ERROR O MISTAKE 12 TAPE NOT STANDARD LENGTH O ERROR O MISTAKE O O

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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1. Two identical channel Sections placed back to back with a clear distance of 50 mm. Given: Channel section C9x13.4 Wide Flange Section W10x33 Angle section L6x4x 3/4 a. Area b. Centroid c. moment of inertia (lx and ly) d. section modulus ( Sx and Sy) e. radius of gyration ( rx and ry)
10. TAPE MEASUREMENTSa. A line was recorded as 1750.00 meters long. It is measured with a 0.65 kg standard tape30.00m long at 20°C under a 50N pull supported at both ends. During the measurementthe temperature was 5°C and the tape was suspended under a 75N pull. It was also foundthat the tape is 3.0mm too short. The line was inclined on a 3% grade. What is the trueinclined distance? E = 200GPa, A = 2.50mm² and the coefficient of linear expansion is0.0000116 m/°C.b. A line was recorded as 2350.00 meters long. It is measured with a 0.65 kg standardtape 30.00m long at 20°C under a 50N pull supported at both ends. During themeasurement the temperature was 5°C and the tape was suspended under a 75N pull.It was also found that the tape is 3.0mm too short. The line was inclined on a 3% grade.What is the true inclined distance? E = 200GPa, A = 2.50 mm² and the coefficient of linearexpansion is 0.0000116 m/°C.
Given: Std. Temp. = 68°F, Std. Length = 100.00’ Std. pull (supported) = 12 lbs. E=29,000,000 lbs./in.Std. pull (unsupported) = 20 lbs. A (cross sectional area of tape) = 0.005 in.².A line was measured and recorded as 275.50’ on a day when the temperature was 28 F. The tape used to measure theline was found to be 99.975 feet long when compared to a standardized tape of 100 feet. Tape is unsupported. What isthe actual measurement of the line? All other conditions are standard
E = 200GPa A= 1100mm^2
Use fc=14.3N/mm^2 ft=1.43N/mm^2 HRB400 fy=360N/mm^2
Findtheradiusofasimplecurve havingadegreeofcurve of 5°using chord basis select the correct answer: A. 229.26 mB. 234.16mC. 223.56mD. 234.16 m
Please make the solutions explicitly and simplify the finalanswer Thankyou. Given Variable: P (kN) = 52
Ʈallow (MPa)=95 Ø(rad)=0.015 a (mm)=80 d (mm)=40
*pls refer to image for correct data. A 50 m steel tape weighs 0.05 kg/m and it is supported at its end points and at 16 m and 27 m marks. If a pull of 55 N is applied during measurement, a) Compute the sag correction between 0 m to 16 m marks. b) Compute the sag correction between 16 m to 27 m marks. c) Compute the sag correction between 27 m to 50 m marks. d) Compute the sag correction for one tape length. e) Compute the correction distance between the ends of the tape.
I cannot understand these For point of contraflexural, 40090300=200×x90300 x=2 m θA=0 (fixed support) θDA=θD-θA=θD=Area of MEI Dia between A and D = 19030012×600×3+600×4+12×300×3-12×200×2 =355090300 θD=0.03931 radianθD= 2.252° Deflection at point D ∆D=31-CosθD ∆D=2.3176×10-3 mm Deflection at point D is 2.3176×10-3 mm
P = 53 kips Z = 8 inches
-Problem XYZ. A steel tape is 100 m long at a standard pull of 65 N. Compute the pull correction in mm if during measurement the applied pull is 40N. The tape has a cross sectional of 3.18 mm^2 and E=200GPa. If the measured length of the line is 865.30, what is the corrected distance? CHOICES: A. 3.93MM, B. 3.94MM, C. 3.95MM, D. NONE OF THE ABOVE -On Problem XYZ. If the measured length of the line is 865.30, what is the corrected distance? CHOICES: A. 865.266, B. 865.301, C. 865.27, D. NONE OF THE ABOVE