Recall that the domain of a rational function A2 is all values of x except those values for which Q(x) = 0. Q(x) Solve 6x - 9 = 0 for x. 6x - 9 = 0 X = х+ 1 Therefore the domain of f(x) = is all real numbers except x = 6x - 9 x + 1 x + 1 Because it is a rational function, f(x) = is continuous over its domain. Thus, f(x) = is discontinuous at 6х- 9 бх - 9 the point x = since this is the value at which f(x) is not defined.

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter3: Polynomial And Rational Functions
Section: Chapter Questions
Problem 11T: Consider the following rational functions: r(x)=x2x22x1 s(x)=x2+4x3+27 t(x)=x+2x39x u(x)=x225x2+x6...
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Recall that the domain of a rational function 2 is all values of x except those values for which Q(x) = 0.
Q(x)
Solve 6x – 9 = 0 for x.
6x – 9 = 0
X =
x + 1
Therefore the domain of f(x) =
is all real numbers except x =
бх — 9
x + 1
x + 1
Because it is a rational function, f(x) =
is continuous over its domain. Thus, f(x)
is discontinuous at
бх — 9
бх — 9
the point x =
since this is the value at which f(x) is not defined.
Transcribed Image Text:Recall that the domain of a rational function 2 is all values of x except those values for which Q(x) = 0. Q(x) Solve 6x – 9 = 0 for x. 6x – 9 = 0 X = x + 1 Therefore the domain of f(x) = is all real numbers except x = бх — 9 x + 1 x + 1 Because it is a rational function, f(x) = is continuous over its domain. Thus, f(x) is discontinuous at бх — 9 бх — 9 the point x = since this is the value at which f(x) is not defined.
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