Reduce the system to two equations in two variables. Because Equation 1 contains only x and z, we can omit one of the elimination steps by eliminating y using Equations 2 and 3. This will give us two equations in x and z. To eliminate y using Equations 2 and 3, we multiply Equation 2 by -2 and add Equation 3. Sx + y + 2z = lx + 2y + z = 16 Multiply by -2. No change (Equation 2) 17 -2x – 2y – 4z -34 (Equation 3) x + 2y + z = 16 Add: 3z = -18 Equation 4

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter13: Conic Sections
Section13.5: Systems Involving Nonlinear Equations
Problem 39PS
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Reduce the system to two equations in two variables. Because Equation 1
contains only x and z, we can omit one of the elimination steps by eliminating y using
Equations 2 and 3. This will give us two equations in x and z. To eliminate y using
Equations 2 and 3, we multiply Equation 2 by -2 and add Equation 3.
Sx + y + 2z =
lx + 2y + z = 16
Multiply by -2.
No change
(Equation 2)
17
-2x – 2y – 4z
-34
(Equation 3)
x + 2y + z =
16
Add:
3z = -18 Equation 4
Transcribed Image Text:Reduce the system to two equations in two variables. Because Equation 1 contains only x and z, we can omit one of the elimination steps by eliminating y using Equations 2 and 3. This will give us two equations in x and z. To eliminate y using Equations 2 and 3, we multiply Equation 2 by -2 and add Equation 3. Sx + y + 2z = lx + 2y + z = 16 Multiply by -2. No change (Equation 2) 17 -2x – 2y – 4z -34 (Equation 3) x + 2y + z = 16 Add: 3z = -18 Equation 4
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