Refer to Fig. TOS-OM-07. For the indeterminate beam shown, assume El = constant, solve for the following Vertical Reaction at support A in kN 40KN 20KN 30KN/m 30KN/m B. 2m 3m 2m 1m Fig. TOS-OM-07 Zoom image 24.54 42.45 131.81 113.18
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- Determine the deflection at midspan of the structure Group of answer choices (-5wL^4)/384EI (5wL^4)/384EI (wL^3)/24EI (-wL^3)/24EIDetermine the slope at point A and the deflection at point C of the beam shown by the conjugate-beam method. 180 KN -3 m- B 3 m- Hinge C I=2080 x 106 mm² D -3 m————5 m- E E = 200 GPa I= 1040x106 mm² 67.5 kl -3 m- F(a) Compute the vertical deflection at C, the horizontal deflection at D and the rotation at A by the virtual work method. (b) If support E moves to the right by 5mm and settles downward by 10mm, compute the additional horizontal deflection at D. Given E=200GPa and I=108mm4 .
- The slotted arm OA rotates about a fixed axis through O. At the instant under consideration, θ = 32°, θ˙ = 47 deg/s, and θ¨ = 21 deg/s2. Determine the magnited of the force F applied by arm OA and the magnitude of the force N applied by the sides of the slot to the 0.3-kg slider B. Neglect all friction, and let L = 0.64 m. The motion occurs in a vertical plane.Moment Distribution Method Given the continous Beam Determine the following: A. Supports Reaction b. Draw the Shear and Moment Diagram AB=3I BC=10I CD=2IC0nsider the frame bel0w where f0rce A = 55 N acts 0n p0int Q, f0rce B = 34 N acts on p0int P, and force C = 42 N acts on p0int M. Replace the system of f0rces acting on the frame with two f0rces, one acting on p0int O and the other acting vertically at point P. Calculate the magnitude and direction of the vertical f0rce acting on p0int P, FP, and the force acting on p0int O, FO.
- Solve the following indeterminate beam by the moment distribution method. Determine the reactions and draw the bending moment diagram. (Ans : Ay=4.156, By=10.839, Cy=34.937, Dy=30.068, MAB=-0.677, MBA=17.396, MBC=-17.396, MCB=16.929, MCD=-16.929, MDC=10.285 )1.What is the maximum intensity of moment for the beam loaded as shown? -20 KN-m -40 KN-m -80 KN-m -72 KN-m 2.What is the shear value at point just before C? 40KN 72KN 80KN 32KN 3.What is the shear value at point just after D? 80KN 72KN 32KN 40KN 4.What is the moment value at B? -72 KN-m -40 KN-m -20 KN-m -80 KN-m 5.What is the value of x, the additional point of zero shear from C? 3.0 m 1.6 m 2.67 m 2.4 m 6.What is the degree of curve in the shear diagram…Determine the solution for the bar forces in the truss shown when P = 1 kip and x = 5 ft: AC = -1732.05 AB = 2000 BC = -866.03 BD = 2500 DC = 2020.73 EC = -3175.43
- Before the load P was applied, a gap, ?0(2.75mm) existed between the cantilever beam AC andthe support at B. Knowing that E=200 GPa, determine the magnitude of P for which thedeflection at C is δ(5.5mm) and the reaction at B. (Hint: Use the method of superposition and beam deflections in Appendix A)20 -In the cantilever beam in the figure, bar clearance L= 225 cm and single load acting on the free end of the bar P = 12 kN. The cross-sectional effects at point B will be calculated. Accordingly, the Moon on the fixed support at point A=? A) None.B) 27000C) 12000D) 0E) 9000Determine the following unknowns on the beam shown below using Area-Moment Method. Consider 150 mm x 150 mm section and E = 80 GPa. Note that: a = 3.7 m b = 31.0 kN/m c = 35 kN Find the ff. A. Vertical reaction at B in kN. B. Moment reaction at A in kN-m. C. Deflection at point C in mm. D. Deflection at midspan of AB in mm.