Referring to question 13, if the two offspring were to mate with each other, what is the probability that the first three female offspring will be black? O 1/4 O 1/64 1/8 3/8 O 1/16
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A: Ans: 50% heterozygous
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A: Option a.) Gg
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Q: What is the probability that one of their children would be a carrier? О3/4 O 1/4 O 1/2
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- In humans the absence of a cleft chin is dominant to the presence of a cleft chin. Two individuals, both of whom are heterozygous for a recessive allele that causes the cleft chin phenotype have 5 children, what is the probability that 3 of their children would not have a cleft chin and 2 would have a cleft chin? 0.0037 0.026 0.237 0.264In rabbits grey hair is dominant to white & black eyes are dominant to red. -Cross 2 parents who are both heterozygous for both traits. 1st Question to answer ---- How many of the offspring could have grey hair & black eyes? 2nd Question to answer ---- How many of the offspring could have grey hair & red eyes? 3rd Question to answer ---- How many of the offspring could have white hair & black eyes? 4th Question to answer ---- How many of the offspring could have white hair & red eyes?ASAP PLEASE In Talons, the feral style (S) is dominant over the gladiator style (s), and green eyes (G) are dominant over yellow (g). If a Talon that is heterozygous for both traits is crossed with a Talon that is homozygous recessive for both traits, what is the predicted genotype of the offspring? A)SsGg and Ssgg B)SsGg only C)SsGg, ssgg, ssGg, Ssgg D)ssGg and ssgg only
- Consider the following scenario: A man without freckles (freckles are a dominant trait, determined by the dominant allele “F”) is a carrier of cystic fibrosis (recall that CF is a recessive trait, determined by the recessive allele "a"), mates with a woman whose genotype is heterozygous for freckles and is also a carrier of CF. Assume the two genes in question are in different chromosomes and, therefore, assort independently. Complete the following Punnett square to generate the offspring probabilities from this couple, by entering the genotypes of the parents, the gametes, and the offspring for the two traits described above. (4) Father’s genotype ffAa Mother’s genotypeFfAa ● Sperm: fA ● Sperm: fa ● Sperm: fA ● Sperm: fa ● Egg: FA ● Egg: fA ● Egg: Fa ● Egg: fa What is the probability for this couple to have a child with freckles? What is the…An individual with a form of red-green color blindness processes a genetically inherited trait that makes it difficult to distinguish red and green color hues. Red-green color blindness tends to skin generations and it is found much more often in men than in women. If a man who was normal and a woman who is a carrier for this form of colorblindness have a child, when the probability that the child will be red-green colorbind is: -0% -25% -50% -75% -100%n Figure 6-6, assess the allele Vfwith respect to the Vbyallele: is it dominant? recessive? codominant? incompletely dominant?
- Scenario A In goats, black fur is dominant to red fur. The gene for this trait can be described as Bb (if you forgot why this is so, go back and reread the background information at the beginning of this exercise). A homozygous black female goat (nanny) is crossed with a heterozygous male (billy). 1 What is the genotype of the nanny? What is the phenotype of the nanny?How does incomplete dominance differ from incomplete penetrance?a. Incomplete dominance refers to alleles at the same locus; incomplete penetrance refers to alleles at different loci.b. Incomplete dominance ranges from 0% to 50%; incomplete penetrance ranges from 51% to 99%.c. In incomplete dominance, the heterozygote is intermediate between the homozygotes; in incomplete penetrance, heterozygotes express phenotypes of both homozygotes.d. In incomplete dominance, the heterozygote is intermediate between the homozygotes; in incomplete penetrance, some individuals do not express the expected phenotypeI have a biology question, this is a matching question, which is only used once: The phenotype of the heterozygote is a blending of the phenotypes of both homozygotes. One allele masks the expression of the only other allele for the trait. One gene pair will interact so as to control the expression of a second gene pair One example is the ABO blood group system. When 3 or more pairs of genes control the expression of a trait. matched with: multiple alleles incomplete dominance polygenics dominance epistasis
- In dogs, coat color maybe black, brown or white. A series of crossings between black and white dogs gave the following F2 results: 28 BLACK:13 WHITE: 9 BROWN. What is the expected F2 phenotypic ratio?In cows, there is a "splotchy" phenotype that is splotches of brown and white. A true-breeding white cow (homozygous recessive) is bred to a true-breeding brown cow (homozygous dominant). In the resulting offspring, 75% have spots of brown and white and 25% are brown. The phenotype described displays what kind of relationship(s) between alleles? Incomplete penetrance Incomplete penetrance Variable expressivity Variable expressivity Incomplete dominance Incomplete dominance CodominanceCan ypu answer ALL parts to this question Pigment of chicken feathers is regulated by two genes, the gene for feather pigment C, and a gene that inhibits pigment production, I. A mother chicken, who is heterozygous for gene c, and heterozygous for gene I, is crossed with a father chicken, who is homozygous recessive for the pigment gene, and heterozygous for gene I. Inhibition is dominant to uninhibited, pigmented feathers are dominant to unpigmented feathers. The inhibitor gene (I) will prevent expression of pigmented chicken feathers. Use the letters C, c, I, and i for the genes. C is for color and I is for inhibitor Enter your answer as a list of haplotypes separated by spaces such as AB ab Ab aB. Do not write a sentence. Do not list duplicate haplotypes. Alphabatize your haplotypes, e.g. Ab, not bA. A) What are the potential genotypes of the gametes produced by the mother for these two genes? B) What are the potential genotypes of the gametes produced by the father for…