Remember, even if you enter an answer rounded to a set number of decimal places, if you use that number in a future calculation, you should use all of the decimal places reported on your calculator! Solve triangle ABC if ZA = 38.2, a = 188.3, and b 248.6. = sin B = 54.1 (round answer to 5 decimal places) There are two possible angles B between 0 and 180° with this value for sine. Find the two angles, and report them so that ZB₁ is the acute angle. LB₁ = and LB₂ = (round these and all remaining answers to 1 decimal place) Thus, two triangles satisfy the given conditions: triangle A1B₁C₁ and triangle A2 B2C2. Solve the first triangle: A₁B₁C₁ ZC₁ = and C1 = Solve the second triangle: A2 B2C2 LC₂ = and C2 =

Trigonometry (MindTap Course List)
8th Edition
ISBN:9781305652224
Author:Charles P. McKeague, Mark D. Turner
Publisher:Charles P. McKeague, Mark D. Turner
Chapter2: Right Triangle Trigonometry
Section: Chapter Questions
Problem 1RP: The origins of the sine function are found in the tables of chords for a circle constructed by the...
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Remember, even if you enter an answer rounded to a set number of decimal places, if
you use that number in a future calculation, you should use all of the decimal places
reported on your calculator!
Solve triangle ABC if ZA = 38.2, a = 188.3, and b = 248.6.
sin B = 54.1
(round answer to 5 decimal places)
There are two possible angles B between 0 and 180° with this value for sine. Find the two angles, and
report them so that ZB₁ is the acute angle.
ZB₁
and
ZB₂ =
=
(round these and all remaining answers to 1 decimal place)
Thus, two triangles satisfy the given conditions: triangle A1B₁C₁ and triangle A2 B2C2.
Solve the first triangle: A1B1C₁
ZC1 =
and C₁ =
Solve the second triangle: A2 B2C2
LC₂ =
and C2 =
Transcribed Image Text:Remember, even if you enter an answer rounded to a set number of decimal places, if you use that number in a future calculation, you should use all of the decimal places reported on your calculator! Solve triangle ABC if ZA = 38.2, a = 188.3, and b = 248.6. sin B = 54.1 (round answer to 5 decimal places) There are two possible angles B between 0 and 180° with this value for sine. Find the two angles, and report them so that ZB₁ is the acute angle. ZB₁ and ZB₂ = = (round these and all remaining answers to 1 decimal place) Thus, two triangles satisfy the given conditions: triangle A1B₁C₁ and triangle A2 B2C2. Solve the first triangle: A1B1C₁ ZC1 = and C₁ = Solve the second triangle: A2 B2C2 LC₂ = and C2 =
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