Remember if you have a question about this, you can email/send me a message on Teams. I want to help you succeed! 1. Show that 2! 4! 6! (2n)! ≥ ((n + 1)!)” for n € Z+. 2. Show that a + (a+d) + (a+2d) + (a +3d) ++(a + (n-1)d) = n(2a + (n-1)d) 2 for ne Z+.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section9.2: Systems Of Linear Equations In Two Variables
Problem 38E
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Learning Target R4 Core: Given a statement to be proven by (weak) induction, I can state and prove the base case,
state the inductive hypothesis, and outline the proof. I can describe the subtle difference between 'weak' and 'strong'
induction.
For each statement below, complete each of the following parts:
. State and prove the base case
State the inductive hypothesis
• Outline how the rest of the proof would go, that is, tell me roughly what will happen to complete the
proof, identifying how this section of the proof will begin and ultimately what it will look like when
you're done (as modeled in class videos); you do not need to actually do the complete proof.
You might not be able to prove these claims with what we learned in this class, and that's okay. You're just
setting it up!
Remember if you have a question about this, you can email/send me a message on Teams. I want to
help you succeed!
1. Show that 2! 4! 6! (2n)! ≥ ((n + 1)!)" for n € Zt.
2. Show that a + (a+d) + (a + 2d) + (a + 3d) ++ (a + (n − 1)d) =
n(2a + (n-1)d)
2
for ne Zt.
Transcribed Image Text:Learning Target R4 Core: Given a statement to be proven by (weak) induction, I can state and prove the base case, state the inductive hypothesis, and outline the proof. I can describe the subtle difference between 'weak' and 'strong' induction. For each statement below, complete each of the following parts: . State and prove the base case State the inductive hypothesis • Outline how the rest of the proof would go, that is, tell me roughly what will happen to complete the proof, identifying how this section of the proof will begin and ultimately what it will look like when you're done (as modeled in class videos); you do not need to actually do the complete proof. You might not be able to prove these claims with what we learned in this class, and that's okay. You're just setting it up! Remember if you have a question about this, you can email/send me a message on Teams. I want to help you succeed! 1. Show that 2! 4! 6! (2n)! ≥ ((n + 1)!)" for n € Zt. 2. Show that a + (a+d) + (a + 2d) + (a + 3d) ++ (a + (n − 1)d) = n(2a + (n-1)d) 2 for ne Zt.
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