Question Help ▼Resource allocation. A coffee manufacturer uses Colombian and Brazilian coffee beans to produce two blends, robust and mild. A pound of the robustblend requires 12 ounces of Colombian beans and 4 ounces of Brazilian beans. A pound of the mild blend requires 6 ounces of Colombian beans and10 ounces of Brazilian beans. Coffee is shipped in 130-pound burlap bags. The company has 48 bags of Colombian beans and 45 bags of Brazilianbeans on hand. How many pounds of each blend should they produce in order to use all the available beans?Robust = IbsMild =Ibs(Round each answer to the nearest pound.)Do you want to switch to tablet mode?This makes Windows more touch-friendlywhen using your device as a tablet.Enter your answer in each oft the answer bosesAlways ank me before switchingType here to search

Name: Question Help ▼Resource allocation. A coffee manufacturer uses Colomb
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Description: Question Help ▼Resource allocation. A coffee manufacturer uses Colombian and Brazilian coffee beans to produce two blends, robust and mild. A pound of the robustblend requires 12 ounces of Colombian beans and 4 ounces of Brazilian beans. A pound of

Answered: Resource allocation. A coffee…

Linear Algebra: A Modern Introduction

4th Edition

ISBN:9781285463247

Author:David Poole

Publisher:David Poole

Chapter2: Systems Of Linear Equations

Section2.4: Applications

Problem 5EQ: 5. A coffee merchant sells three blends of coffee. A bag of the house blend contains 300 grams of...

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Given that a pound of robust requires 12 ounces of Colombian beans and 4 ounces of Brazilian beans.

Similarly a pound of mild blend requires 6 ounces of Colombian beans and 10 ounces of Brazilian beans.

Coffee is shipped in 130-pound bags and company has 48 bags of Colombian and 45 bags of Brazilian beans.

Let x denote the number of pounds of robust blend and y denote the number of pounds of mild blend.

Form the below table using given information.

	x	y	Available
Colombian(pounds)	$\frac{12}{16}$	$\frac{6}{16}$	$48 \times 130 = 6240$
Brazilian(pounds)	$\frac{4}{16}$	$\frac{10}{16}$	$45 \times 130 = 5850$

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