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road at an extremely high rate of speed may be about as safe as riding a rhino. You continue to accelerate at 1.3m/s' until you reach a speed of 32 m/s. How long did it take you to reach this speed? How far have you gone? You see a very sharp turn 27m ahead and realize that you need to stop before you reach the turn or else you will go off the road and over the cliff and your

road at an extremely high rate of speed may be about as safe as riding a rhino. You continue to accelerate at 1.3m/s' until you reach a speed of 32 m/s. How long did it take you to reach this speed? How far have you gone? You see a very sharp turn 27m ahead and realize that you need to stop before you reach the turn or else you will go off the road and over the cliff and your

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter2: Motion In One Dimension
Section: Chapter Questions
Problem 13P: A person lakes a trip, driving with a constant speed of 89.5 km/h, except, for a 22.0-min rest stop....
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road at an extremely high rate of speed may be about as safe as riding a rhino. You continue to accelerate at 1.3m/s' until you reach a speed of 32 m/s. How long did it take you to reach this speed? How far have you gone? You see a very sharp turn 27m ahead and realize that you need to stop before you reach the turn or else you will go off the road and over the cliff and your
Transcribed Image Text:road at an extremely high rate of speed may be about as safe as riding a rhino. You continue to accelerate at 1.3m/s' until you reach a speed of 32 m/s. How long did it take you to reach this speed? How far have you gone? You see a very sharp turn 27m ahead and realize that you need to stop before you reach the turn or else you will go off the road and over the cliff and your
Expert Solution
Step 1

The bike starts from rest .Hence the initial velocity u=0 m/s

The acceleration of the bike a =1.3 m/s2

The velocity reached with this velocity v=32 m/s

The time taken 't' to reach the velocity 32 m/s is calculated as follows

v=u+att=v-uat=32-0m/s1.3 m/s2t=24.62 s

The distance moved '∆x' in this time is calculated as follows 

v2=u2+2a∆x∆x=v2-u22a∆x=32m/s2-021.3m/s2∆x=393.85 m393.85 m

 

Step 2

The speed of the bike when the sharp turn is seen u1=32 m/s

The distance moved before the bike is stopped ∆x1=27 m

The final velocity of the bike when it is stopped v1=0 m/s

The acceleration of the bike is 

v12=u12+2a1∆x10=32 m/s2+2a27 ma1=-32 m/s2227 ma1=-18.96 m/s2

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