Rope 1 A B TE Rope 2 The diagram shows two 1.00 kg blocks connected by a rope. A second rope hangs beneath the lower block. Both ropes have a mass of 0.500 kg. The entire assembly is accelerated upward at 2.40 m/s² by force F. Assuming that the local acceleration due to gravity is -9.80 m/s2, what is F? Submit Answer Tries 0/10 What is tension in top end of rope 1? Submit Answer Tries 0/10 What is tension in bottom end of rope 1? Submit Answer Tries 0/10

Rope 1 A B TE Rope 2 The diagram shows two 1.00 kg blocks connected by a rope. A second rope hangs beneath the lower block. Both ropes have a mass of 0.500 kg. The entire assembly is accelerated upward at 2.40 m/s² by force F. Assuming that the local acceleration due to gravity is -9.80 m/s2, what is F? Submit Answer Tries 0/10 What is tension in top end of rope 1? Submit Answer Tries 0/10 What is tension in bottom end of rope 1? Submit Answer Tries 0/10

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Description: Rope 1Rope 2FATELBC209 Pearson Education, the using as Pearson AnThe diagram shows two 1.00 kg blocks connected by a rope. A second rope hangs beneath the lower block. Both ropes have a mass of 0.500 kg. The entire assembly is accelerated upward at

Inquiry into Physics

8th Edition

ISBN:9781337515863

Author:Ostdiek

Publisher:Ostdiek

Chapter2: Newton's Laws

Section: Chapter Questions

Problem 11P: . A person stands on a scale inside an elevator at rest (Figure 2.54). The scale reads 800 N. (a)...

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A block of mass 3m is placed on a frictionless horizontal surface, and a second block of mass m is placed on top of the first block. The surfaces of the blocks are rough. A constant force of magnitude F is applied to the first block as in Figure P4.68. (a) Construct free-body diagrams for each block. (b) Identify the horizontal force that causes the block of mass m to accelerate. (c) Assume that the upper block does not slip on the lower block, and find the acceleration of each block in terms of m and F. Figure P4.68
Train Collision and Newtons First Law A group of college students discusses the train collision case study. Use Newtons first law to decide which underlined statements are correct and which are false. Explain your answers. Shannon: This newspaper says that the people who got really hurt were either standing up or sitting in a forward-facing seat. Those people got thrown forward when the train stopped. Avi: Thats why there are seat belts in cars. If you get into a crash, the force can throw you through the windshield. Cameron: There is no force that throws you through the windshield. You fly through the windshield because you are already moving and it would take a force to stop you from going forward. Thats why theres a seat belt. Avi: That doesnt make sense. Because then you would need a force to stop you from flying through the windshield even when you just stop slowly at a red light. Cameron: Thats right, but when you slow down slowly, you dont need such a big force and the car seat can take care of it. Shannon: The seat? I dont think a seat can exert a force. It cant move on its own or hold you. Thats why the people who were sitting forward on the train were hurt. The people who were sitting backward had the back of the seat to block them.
A weight lifter stands on a bathroom scale. (a) As she pumps a barbell up and down, what happens to the reading on the scale? (b) Suppose she is strong enough to actually throw the barbell upward. How does the reading on the scale vary now?
When a 1.50-kg dress hangs midway from a taut clothesline stretched between two poles planted 7.50 m apart, the clothesline is seen to sag 0.0500 m. a. Draw a free-body diagram of the dress. b. What is the tension produced on the clothesline by the dress? Assume the clothesline is massless.
. A person stands on a scale inside an elevator at rest (Figure 2.54). The scale reads 800 N. (a) What is the person's mass? (b) The elevator accelerates upward momentarily at the rate of 2 m/s2. What does the scale read then? (c) The elevator then moves with a steady speed of 5 m/s. What does the scale read now?
A block of ice (m = 15.0 kg) with an attached rope is at rest on a frictionless surface. You pull the block with a horizontal force of 95.0 N for 1.54 s. a. Determine the magnitude of each force acting on the block of ice while you are pulling. b. With what speed is the ice moving after you are finished pulling?
When you learn to drive, you discover that you need to let up slightly on the brake pedal as you come to a stop or the car will stop with a jerk. Explain this in terms of the relationship between static and kinetic friction.
Chris, a recent physics major, wanted to design and carry out an experiment to show that an objects mass determines its inertia. He used an ultrasound device to measure acceleration of a low-friction cart attached to a hanging block to provide the same force on the cart during each run (Fig. P6.76A). Chris varied the mass of the cart by varying the number of lead rods placed in it. Chris used Newtons second law Fx=FT=Max to predict his results. He reasoned that because FT is the same for each run, the carts acceleration should be inversely proportional to its mass: ax=FTM=constantM(1) Chriss goal was to show that his data fit Equation (1). He decided to analyze his results by plotting ax as a function of 1/M; Equation (1) predicted that he should get a straight line, passing through the origin with a slope equal to the tension (red line in Fig. P6.76B): Chris ran several trials for each run, averaged his results and estimated the error. He then plotted his data (green line in Fig. P6.76B). Chris was excited to see that he correctly predicted that the data fell along a straight line: ax=(0.27N)1M(0.048m/s2) According to the straight-line fit to the data, the slope of the line is 0.27 N, which was close to the weight of the hanging mass and therefore close to the tension in the string. Chris, though, was disappointed to see that the line had a negative intercept. Mathematically, as M, 1M0. Chris was confused because he believed that as the mass increased, the carts acceleration should approach zero. He was quite sure that he did not discover some new property of inertia or mass. After convincing himself that he was not being careless in the laboratory and that his data were correct, he started to search for an explanation for the discrepancy between his prediction and his data. Help Chris find an explanation. FIGURE P6.76 A. Chriss experimental apparatus. B. Chriss prediction (red line) and experimental results (green line).
A person holds a ball in her hand. (a) Identify all the external forces acting on the ball and the Newtons third-law reaction force to each one. (b) If the ball is dropped, what force is exerted on it while it is falling? Identify the reaction force in this case. (Ignore air resistance.)
Which statement is correct? (a) Net force causes motion. (b) Net force causes change in motion. Explain your answer and give an example.
A 80.0 kg person is being pulled away from a burning building as shown in the figure below. a) Calculate the tension (in N) in the first rope, T1, if the person is momentarily motionless. N b) Calculate the tension (in N) in the second rope, T2, if the person is momentarily motionless. N c) Include a free-body diagram in your solution. (Submit a file with a maximum size of 1 MB.)
Q13: A boy throws a steel ball straight up. Consider the motion of the ball only after it has left the boy's hand but before it touches the ground, and assume that forces exerted by the air are negligible. For these conditions, the force(s) acting on the ball is (are): a downward force of gravity along with a steadily decreasing upward force. a steadily decreasing upward force from the moment it leaves the boy's hand until it reaches its highest point; on the way down there is a steadily increasing downward force of gravity as the object gets closer to the earth. an almost constant downward force of gravity along with an upward force that steadily decreases until the ball reaches its highest point; on the way down there is only a constant downward force of gravity. an almost constant downward force of gravity only. none of the above. The ball falls back to ground because of its natural tendency to rest on the surface of the earth.