(Rudin, Ch. 6, Exercise 6) Divide the unit interval [0, 1] into thirds and remove the open interv 1 G). What remains is a pair of closed intervals, each of them one-third as long as the original. F each of the remaining intervals, do this again, i.e., divide the interval into thirds and remove the ope middle interval. Repeating the process over and over again, what is left in the limit is the Cante middle-thirds set C.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
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Chapter10: Sequences, Series, And Probability
Section: Chapter Questions
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(Rudin, Ch. 6, Exercise 6) Divide the unit interval [0, 1] into thirds and remove the open interval
G,). What remains is a pair of closed intervals, each of them one-third as long as the original. For
each of the remaining intervals, do this again, i.e., divide the interval into thirds and remove the open
middle interval. Repeating the process over and over again, what is left in the limit is the Cantor
middle-thirds set C.
Let f : [0, 1]] → R be a bounded function that is continuous at every point in [0, 1] \ C. Show that f
is Riemann integrable on [0, 1]. (Hint: Use the argument of Theorem 6.10 from Rudin).
Transcribed Image Text:(Rudin, Ch. 6, Exercise 6) Divide the unit interval [0, 1] into thirds and remove the open interval G,). What remains is a pair of closed intervals, each of them one-third as long as the original. For each of the remaining intervals, do this again, i.e., divide the interval into thirds and remove the open middle interval. Repeating the process over and over again, what is left in the limit is the Cantor middle-thirds set C. Let f : [0, 1]] → R be a bounded function that is continuous at every point in [0, 1] \ C. Show that f is Riemann integrable on [0, 1]. (Hint: Use the argument of Theorem 6.10 from Rudin).
Expert Solution
Step 1

Given that:

 

The interval [0,1] is given. divide the [0, 1] into 3 subintervals and delete the open middle subinterval and delete the open middle subinterval (1/3, 2/3), leaving two intervals [0,1/3] U [2/3, 1]

 

Now, again divide each of the 2 resulting intervals above into the open middle third subinterval of each subinterval of each interval obtained in the previous step.

 

And continue the process, and each step, delete the open middle third subinterval of each interval.

 

Here objective is to find the limit of the Cantor middle-thirds set C.

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