Run Time Analysis Provide the tightest big-Oh bound on the run time for each of the following methods.    void padawan(int n) {       if( n <= 1 )             time++;       else       {             for(int i=0; i

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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  1. Run Time Analysis

Provide the tightest big-Oh bound on the run time for each of the following methods. 

  1.  

void padawan(int n)

{

      if( n <= 1 )

            time++;

      else

      {

            for(int i=0; i<n; i++)

                        time++;

 

            padawan(n/3);

            padawan(n/3);

            padawan(n/3);

      }

}

 

  1.  

void nerfHerder(int n)

{

      if( n <= 1 )

            time++;

      else

      {

            for(int i=0; i<n; i++)

                  time++;

 

            nerfHerder(n-1);

      }

}

 

  1.  

void squire(int n)

{

      if( n <= 1 )

            time++;

      else

      {

            squire(n/2);

            squire(n/2);

 

            for(int i=0; i<n; i++)

                  for(int j=i; j<n; j++)

                        time++;

 

            squire(n/2);

            squire(n/2);

            squire(n/2);

            squire(n/2);

            squire(n/2);

            squire(n/2);

      }

}

 

  1.  

void jedi(int n)

{

      if( n <= 147 )

            time += 54;

      else

      {

            for(int i=0; i<n/2; i++)

                  time++;

 

            jedi(n/3);

 

            for(int i=0; i<13*n; i++)

                  time++;

 

            jedi((2*n)/3);

      }

}

 

  1.  

void strass(int n)

{

   if( n<=1 )

         time++;

   else

   {

         strass(n/2);

         strass(n/2);

         strass(n/2);

 

         for(int i=0; i<n; i++)

               for(int j=i; j<n; j++)

                     time++;

 

         strass(n/2);

 

         for(int i=n/2; i<n; i++);

               time ++;

 

         strass(n/2);

         strass(n/2);

         strass(n/2);

   }

}

 

 

  1.  

void sithLord(int n)

{

      if( n <= 200 )

            time += 700;

      else

      {

            sithLord((7*n)/10);

 

            for(int i=0; i<n; i++)

                  time++;

 

            sithLord(n/5);

 

            for(int i=0; i<130*n; i+=10)

                  time++;

      }

}

 

  1.  

void hanoi(int n)

{

      if( n==1 )

            time++;

      else

      {

            hanoi(n-1);

            time++;

            hanoi(n-1);

      }

}

 

 

  1.  

int fib(int n)

{

      if( n==0 )

            return 0;

      else if( n==1 )

            return 1;

      else

      {

            return fib(n-1) + fib(n-2);

      }

}

 

  1.  

int pow(double x, int n)

{

      if( n==0 )

            return 1;

      else

      {

            double halfpower = pow(x,n/2);

            if( n % 2 == 0 )

            {

                  return halfpower*halfpower;

            }

            else

            {

                  return halfpower*halfpower*x;

            }

      }

}

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