s (m) 600 360 (s) 30 40
Q: 0.4m 30 0.2 m
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Q: 100 cm-1 = …. m-1 50 km/hr = ……. mile/hr
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Q: ア-1) P2 , the units of temperature can be: D. When using the equation, %3D 1. Fahrenheit II. Celsius…
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Q: CARien max Pruncfal atres= 30 Mpa Min Pruncifcel atres s =20 MPa %3D
A: Given data S1= 30 MPa . S2= 20 MPa.
Q: 400 N/m В 3 m 3 m
A: Let RA and RB are the reactions at A and B By using law of equilibrium ΣFy =0 RA+RB = (1/2)X400X6…
Q: F. A living room is 7.2 m long and 4.5 m wide. What size would it be on a plan drawn to a scale of…
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Q: 6 m 3m 4 m 4 m 4 m 6 m 3 m m 4 m
A: Write coordinates of A,B,C and DA=0,0,3.5B=3,4,4C=-6,-3,6D=4,-3,4
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Q: 400N 200 Z00 N さ
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Q: the velocity of water (in m/s)
A: Given data; For prototype;vp=1.0×10-5m2/sdp=0.5 mVP=10 m/sFor model;vm=0.89×10-6 m2/sdm=20 mm=0.2…
Q: 600 N/m 2 m 4 m R2 R1
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Q: waten tunnle
A: given water tunnel as shown below
Q: given 9 cm %3D Ege =0.2
A: given:diameter d=9cmQ=0.2m3/sθ=1000
Q: 10 kN 0 r=2m 10 kN
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A: Centroid, also called the center area of anybody is the point at which the whole area of the body…
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A: The Quantity of the water is given as, Q=7.7 L
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A: The given volume of gas is v=5.0 gallons. The unit conversion factor from gallons to cm3 is, 1…
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A: For the given diagram in question, Density of water,ρw=1000kg/m3Density of…
Q: 200 400 500 C. Al
A: mass of block A=200 lb=90.7185Kg ;mass of block B=500 lb=226.7962Kg ;mass of block C=400…
Q: 500 N 300 N 45 2.5 m
A: The given system of force is shown below,
Q: 1. cubic yards equals 297 cu ft.
A: Note: Since you have asked multiple question, we will solve the first question for you. If you want…
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A: Given data: The volume of water, V = 2500 acreˑft. One acre equals, 1acre = 43,560 ft2. One gallon…
Q: The pressure 3 meters below the free surface of a liquid is 3.2 lb/in2. What is the specific gravity…
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Q: :A B Water 0.25 m Mercury (S= 13.6)
A: here Level difference y=0.25 mmanometric fluid specific gravity Sm=13.6Water specific gravity S0=1
Q: p (2/1) u S In (1/2) da
A: the given function is a special integral which can not be solved by ordinary elementary operations.…
Q: 400 N/m
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Q: The specific gravity if steel is 7.9 . What is the volumr in cubic feet of a steel in got weighing…
A: Dear student, we are suppose to solve only one question. Please post other question as a separate…
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Q: 29.20 kg, 4220.29 N
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Q: If specific volume of an oil is 0.0008 m3 /kg, then its specific gravity is 125.000 1.250 0.008…
A: Specific volume=1/ρ=0.0008m3/kg .. given
Q: 70 cm 6 m/s
A: Givenspecific gravity of the fluid S=4.4At L=0 then V=2m/sAT L=70cm tghen V=6m/s
Q: Look up the measurement of the approximate thickness of a human hair. Convert the measurement to an…
A: Human hair is approximately 17 to 181-micron meter
Q: Q 2 6 ft |45° 12 ft A
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Q: Water 0,9 m R = 0,75 m 0,75 m K Water F 1,5 m 2m
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Q: vr is calculated and is equal to
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Q: 5. Weight of an object in air is 10000 dynes. The object is placed in a liquid. Increase in volume…
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Q: OA 6 m 2 m 1.5 m 3 m
A: Given V=6m/s
Q: A bedroom has a volume of 115 m^3. What is its volume in: dm^3
A: Given Volume = 115 m3 1 m3 is = 1000 dm3
Q: и Find the Final uelouity д сам левоск U-2.312 mis а = 2.2 mist += 35
A: Given data : Time=t Initial velocity=U Acceleration=a Required : Final velocity
Q: What is the measurement methods to the following variables? 1- Velocity. 2- Air contaminant level.…
A: following is the answer-
Q: 2 m D 0.6 m 1 m B.
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Q: Based on the picture, devolep 5 question on calculation
A: From the given data: Question: Calculate the PV diagram for water. Mention critical point, critical…
Q: by m+r=2j
A: As per honour code we will answer the first question since exact one was not specified . Please…
Q: ᴀ ᴘᴜᴍᴘ ᴅᴇʟɪᴠᴇʀꜱ 0.3 ᴍ3/ꜱ ᴀɢᴀɪɴꜱᴛ ᴀ ʜᴇᴀᴅ ᴏꜰ 200 ᴍ ᴡɪᴛʜ ᴀ ꜱᴘᴇᴇᴅ ᴏꜰ 2000 ʀᴘᴍ. ꜰɪɴᴅ ᴛʜᴇ ꜱᴘᴇᴄɪꜰɪᴄ ꜱᴘᴇᴇᴅ
A: Given data: Q=0.3 m3/sH=200 mN=2000 rpm Need to determine the specific speed.
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- I have data accrued from a fan could you explain to me the concepts and show me how to calculate the horsepower and work done by the fan that data was composed of below in this table? Time (s) Run #1 Velocity, Blue (m/s) Run #1 0.05 0 0.1 0 0.15 0 0.2 0 0.25 0 0.3 0 0.35 4.04E-04 0.4 4.04E-04 0.45 0 0.5 -4.04E-04 0.55 -4.04E-04 0.6 0 0.65 0 0.7 4.04E-04 0.75 8.08E-04 0.8 4.04E-04 0.85 -4.04E-04 0.9 -8.08E-04 0.95 0 1 8.08E-04 1.05 4.04E-04 1.1 0 1.15 -4.04E-04 1.2 0 1.25 4.04E-04 1.3 0 1.35 0 1.4 -4.04E-04 1.45 0 1.5 4.04E-04 1.55 0 1.6 0 1.65 -4.04E-04 1.7 0 1.75 4.04E-04 1.8 0 1.85 0 1.9 -4.04E-04 1.95 0 2 4.04E-04 2.05 4.04E-04 2.1 4.04E-04 2.15 0 2.2 0 2.25 0 2.3 0 2.35 0 2.4 0 2.45 0 2.5 4.04E-04 2.55 8.08E-04 2.6 8.08E-04 2.65 8.08E-04 2.7 8.08E-04 2.75 8.08E-04 2.8 4.04E-04 2.85 0 2.9 0 2.95 0 3 0 3.05 0 3.1 0 3.15 0 3.2 0 3.25 0 3.3 0 3.35 0…The diagram shows a velocity-time graph for a car moving in a straight line. At point P thecar must be ____ and at point Q it must be ______ CHoices: slowing down, slowing down at the right of the origin, at the left of the origin speeding up, slowing down slowing down, speeding up speeding up, speeding up Explain whyFind the local maximum and minimum values and saddle point(s) of the function. You are encouraged to use a calculator or computer to graph the function with a domain and viewpoint that reveals all the important aspects of the function. (Enter your answers as comma-separated lists. If an answer does not exist, enter DNE.) f(x, y) = 9 sin(x) sin(y), −? < x < ?, −? < y < ? local maximum value(s) local minimum value(s) saddle point(s) (x, y) =
- For the Following question Graph all 4 : [I just need all 4 graphs and please explain and make clean solution] Position vs time Velocity vs time Acceleration vs time Force vs time [For your convenience, I have solved the numerical solutions for the problem] (Please Look at the picture since it is much cleaner) Question : A 550 kilogram mass initially at rest acted upon by a force of F(t) = 50et Newtons. What are the acceleration, speed, and displacement of the mass at t = 4 second ? a =(50 e^t)/(550 ) [N/kg] v = ∫_0^t▒(50 e^t )dt/(550 )= v_0 +(50 e^t-50)/550=((e^t- 1))/11 x = ∫_0^t▒(e^t- 1)dt/(11 )= x_0 +(e^t- t - 1)/(11 ) a(4s)=(50*54.6)/550= 4.96[m/s^2 ] v(4s)=((e^4-1))/11= 4.87[m/s] x(4s)=((e^4- 4 - 1))/11= 4.51 [m]QUESTION ONEUse dimensional analysis and chain link conversion to perform the indicatedconversions.A. 0.8mile/hour to m/sB. 0.0065km2 to m2C. 5500cm3 to m3D. 435000m2 to km2 QUESTION TWOA person in a kayak starts paddling, and it accelerates from 0 to 0.8 mile/hour in adistance of 0.8km. If the combined mass of the person and the kayak is 80kg, whatis the magnitude of the net force acting on the kayak? QUESTION THREEDiscuss three (3) applications and limitations of dimensional analysis?QUESTION FOURState the principle of homogeneity of dimensions? QUESTION FIVEA. A value of the acceleration of free fail g was determined by measuring the periodof oscillation T of a simple pendulum of length l. The relation between g, T andl is given by: ? = 4?(? /?2) In the experiment, l was measured as 0.55±0.02 m and T was measured as1.50±0.02 s. Find the:i. Value of gii. Uncertainty in the value of g B. (a) State newton’s second law of motion and write an equation.(b)Define the term INERTIA. (c)…The motion of a jet plane just after landing on a runway is described by the (v -t ) graph. Construct the (s —t ) and (a — t ) graphs for the motion. Here (s =0 ), when (t=0). =15t +ast v () V= ~15t+600 )
- Applying principles of dynamics (with step by steep solutions pls i give 5 stars) The displacement of a particle which moves along the x axis is given by x = (-4 + 3t2)e-0.25t, consider x to be in feet and t in seconds. Plot the displacement, velocity and acceleration for the first 20 seconds of motion and determine, both graphically and by your established equation for acceleration,the time at which acceleration is 0. (If the students find it more comfortable, they may choose to graph using excel or any graphing software, solutions however must be done manually)Please help answer the question shown in the photo. Please explain clearly why the formulas you picked were used, and what the purpose of each number and variable in your calculation represents. Thank you!A vertical chemical reactor undergone a maintenance in which its internals were subjected inspection from bottom to top before catalyst loading. A site engineer (63.00 kg) was tasked to do the inspection and he stopped from time to time at each portion to inspect. A safety officer monitored the engineer’s position while watching from the top and reported his position (Refer to the photo attached. CORRECTION for data table at t=70.00 min, position=725.0 cm): Solve for: (a) Power he exerted at t = 50.00 min (b) Power he exerted at t = 65.00 min (c) Total Work he exerted throughout the inspection (d) Average Power throughout the inspection
- Use dimentional analysis to evaluate that in a problem involving shallow water waves (figure 6), both the Froude number and the Reynold's number are relevant dimensionless parameters. The wave speed, c of waves on the surface of a liquid is a function of depth h, gravitational acceleration g, fluid density, p and fluid viscosity μ. Manipulate your II's to get the parameters into the following form: Fr = c/(gh)1/2= f(Re) , where Re = pch/μAs the potential across the resistor increased, the current through the resistor increased. If the change in current is proportional to the voltage, the data should be in a straight line and it should go through zero. In these two examples how close is the y-intercept to zero? Is there a proportional relationship between voltage and current? If so, write the equation for each run in the form potential = constant x current. (Use a numerical value for the constant.)A snowboarder’s velocity is tracked by a pulse-laser velocimeter as she descends the slope. These velocity data are stored and analyzed via an embedded curve fitting procedure to determine a velocity function of v(t) = 1.5t2 + 2t + 2 (t is time in seconds and v is velocity in ft/s). At time equal 0, position (x) is zero. Find her position (e.g., distance traveled), velocity and acceleration formulations and values of each when time equals 15 seconds. Clearly write the formulas before finding respective values at t = 15 seconds!