SAMPLE DISPLAY OUTPUT: Arithmetic Operation Enter number 1: 10 Enter number 2:5 [A] [+] Addition [S] [-] Subtraction [M] [*] Multiplication [D] [/] Division [E] [e] Exit Select a character for the operation : + Addition The Result is: 15
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In this output, please create a c++ program and show the picture of the output. Thank youuu
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- Original Sample:------# convert.py # A program to convert Celsius temps to Fahrenheit # from textbook chapter 2 def main(): celsius = eval(input("What is the Celsius temperature? ")) fahrenheit = 9/5 * celsius + 32 print("The temperature is", fahrenheit, "degrees Fahrenheit.") main()Revised Sample:------# convert_revised_1.py # We will try to print a table without using "string formatting"def main():print("celsius", "fahrenheit") for celsius in range (-20, 110, 10):fahrenheit = 9/5 * celsius + 32print(celsius, fahrenheit)main() 1. You can copy/paste the sample program convert_revised_1.py to run and see how it works to make sense first. 2. Your turn: Please revise the above program convert_revised_1.py with "string formatting Basically, you only need to revise the TWO print statements, one is before the "for loop", for Table Header another one is within the "for loop". 3. The output should look similar as below (required width for Celsius value is 45, width Fahrenheit value is 55,…NOTE: *String means (array of characters).*Ways to define string in data segment:1. Str1 DB “ MIcroprocessor lab“2. Str1 DB 'M','I','c', 'r', 'o', 'p','r','o','c','e','s','s ','o','r',' ','l','a','b'given input word, return the list of abbreviations.ex)word => ['word', 'wor1', 'wo1d', 'wo2', 'w1rd', 'w1r1', 'w2d', 'w3', '1ord', '1or1', '1o1d', '1o2', '2rd', '2r1', '3d', '4']""" def generate_abbreviations(word): def backtrack(result, word, pos, count, cur): if pos == len(word): if count > 0: cur += str(count) result.append(cur) return if count > 0: # add the current word backtrack(result, word, pos+1, 0, cur+str(count)+word[pos]) else: backtrack(result, word, pos+1, 0, cur+word[pos]) # skip the current word backtrack(result, word, pos+1, count+1, cur).
- please convert the code to C language#include <iostream>#include <fstream>#include<stdlib.h>#include <cstring>#include <iostream>#include <iomanip>using namespace std;string output;int count = 0;unsigned long int total_traversal = 0; class BitwiseRead {private: char buf; //int first; int nbits; //how many bits have been read from the buffer istream& in;public: /* Initialize a BitwiseRead that will use the given istream for input * */ BitwiseRead(istream & is); /* Fill the buffer from the input */ void fill(); /* Read the next bit from the bit buffer. Fill the buffer form the input * stream first if needed. * Return 1 if the bit read is 1, 0 if bit read is 0 * */ int readBit();}; BitwiseRead::BitwiseRead(istream & is) : in(is) { buf = 0; nbits = 8;} void BitwiseRead::fill() { buf = in.get(); nbits = 0;} int BitwiseRead::readBit() { if(nbits == 8) { fill(); } //uses a mask to extract the nbits'th…# ASCII Table Project * output all bytes from 0 to 255 * if it represents a printable character, print the actual character * if it is not a printable character, print a dash ("-") instead * print out the hexadecimal value of the byte* format the output into 8 columns (one column per byte) * line up all the columns ## TestsWrite at least one unit test. _This implies that you have at least one function you call._ There are at least two functions you could write (based on the product definition)* Assignment: Word operations * * Description: * This assignment asks you to implement common word operations that are * not available in the Scala programming language. The intent is to practice * your skills at working with bits. * */ package wordOps /* * Task 1: Population count (number of 1-bits in a word) * * Complete the following function that takes as parameter * a 32-bit word, w, and returns __the number of 1-bits__ in w. * */ def popCount(w: Int): Int = ??? /* * Task 2: Reverse bit positions * * Complete the following function that takes as parameter * a 16-bit word, w, and returns a 16-bit word, r, such that * for every j=0,1,...,15, * the value of the bit at position j in r is equal to * the value of the bit at position 15-j in w. * */ def reverse(w: Short): Short = ??? /* * Task 3: Left rotation * * Complete the following function that takes two parameters * * 1) a 64-bit word, w, and *…
- Subject: Assembly Language Q: Write a program that displays a string in all possible combinations of foreground and background colors (16 x 16 =256). The colors are numbered from 0 to 15, so you can use a nested loop to generate all possible combinations. Also use a delay of 1s in each foreground color change.Integer base conversion algorithm int_to_base(5, 2) return '101'. base_to_int('F', 16) return 15. """ import string def int_to_base(num, base): """ :type num: int :type base: int :rtype: str """ is_negative = False if num == 0: return '0' if num < 0: is_negative = True num *= -1 digit = string.digits + string.ascii_uppercase res = '' while num > 0: res += digit[num % base] num //= base if is_negative: return '-' + res[::-1] return res[::-1] def base_to_int(str_to_convert, base): """ Note : You can use int() built-in function instead of this. :type str_to_convert: str :type base: int :rtype: int """ digit = {} for ind, char in enumerate(string.digits + string.ascii_uppercase): digit[char] = ind.def print_num_pattern(num1, num2): if num1 <=0: print("0", end="") return print(num1, end="") print_num_pattern(num1 - num2, num2) print(num1, end="") if __name__ == "__main__": num1 = int(input()) num2 = int(input()) print_num_pattern(num1, num2)
- ; initialized data heresection .data msg db "Print String!", 0xamsglen equ $-msg ; string length in bytesSTDOUT equ 1 ; standard output deviceSYS_write equ 1 ; write messageSYS_exit equ 60 ; exit programEXIT_OK equ 0 ; return value ; code goes heresection .text ; The '_start' label identifies the program's entry point for the; linker for the 'nasm' assembler. If you use 'gcc', the entry point; is labeled 'main'global _start_start: ; send message string to standard output mov rsi, msg ; text address mov rdx, msgln ; string length (error here) mov rdi, STDOUT ; output device mov rax, SYS_write ; rax holds the function syscall ; system…In Java Write a program that prints the 128-character ASCII table. It should print the tablein eight tab-separated columns. The first column contains a "Dec" heading (fordecimal number) with the numbers 0 through 31 below it. The second columncontains the ASCII characters associated with the numbers 0 through 31. The nextcolumns contain the subsequent numbers and associated ASCII characters. See thebelow sample output for details. Be aware that that output was produced by aprogram running in a console window in a Windows environment. If you runyour program in a different environment, the first 32 characters and the lastcharacter will probably be different from what’s shown below.Note that some characters display in a non-standard manner. For example, thenumber 7 corresponds to a bell sound. You can’t see a sound, but you can see thevacant spot for 7’s character in the below table. The number 8 corresponds to thebackspace character. You can’t see a backspace, but you can see how the…In Java Write a program that prints the 128-character ASCII table. It should print the tablein eight tab-separated columns. The first column contains a "Dec" heading (fordecimal number) with the numbers 0 through 31 below it. The second columncontains the ASCII characters associated with the numbers 0 through 31. The nextcolumns contain the subsequent numbers and associated ASCII characters. See thebelow sample output for details. Be aware that that output was produced by aprogram running in a console window in a Windows environment. If you runyour program in a different environment, the first 32 characters and the lastcharacter will probably be different from what’s shown below.Note that some characters display in a non-standard manner. For example, thenumber 7 corresponds to a bell sound. You can’t see a sound, but you can see thevacant spot for 7’s character in the below table. The number 8 corresponds to thebackspace character. You can’t see a backspace, but you can see how the…