Sample Input 5 3 89 90 78 93 80 90 91 85 88 86 91 92 83 89 90.5 Sample Output 90.0 91.0 82.0 90.0 85.5 Explanation Marks obtained by student 1: 89, 90, 91 Average marks of student 1: 270/3 = 90 Marks obtained by student 2: 90, 91, 92 Average marks of student 2: 273/3 = 91 Marks obtained by student 3: 78, 85, 83 Average marks of student 3: 246/3 = 82 Marks obtained by student 4: 93, 88, 89 Average marks of student 4: 270/3 = 90 Marks obtained by student 5: 80, 86, 90.5 Average marks of student 5: 256.5/3 = 85.5

Systems Architecture
7th Edition
ISBN:9781305080195
Author:Stephen D. Burd
Publisher:Stephen D. Burd
Chapter8: Data And Network Communication Technology
Section: Chapter Questions
Problem 41VE
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Question
Sample Input
5 3
89 90 78 93 80
90 91 85 88 86
91 92 83 89 90.5
Sample Output
90.0
91.0
82.0
90.0
85.5
Explanation
Marks obtained by student 1: 89, 90, 91
Average marks of student 1:
270/3 = 90
Marks obtained by student 2: 90, 91, 92
Average marks of student 2:
273/3 = 91
Marks obtained by student 3: 78, 85, 83
Average marks of student 3:
246/3 = 82
Marks obtained by student 4: 93, 88, 89
Average marks of student 4:
270/3 = 90
Marks obtained by student 5: 80, 86, 90.5
Average marks of student 5:
256.5/3 =
= 85.5
Transcribed Image Text:Sample Input 5 3 89 90 78 93 80 90 91 85 88 86 91 92 83 89 90.5 Sample Output 90.0 91.0 82.0 90.0 85.5 Explanation Marks obtained by student 1: 89, 90, 91 Average marks of student 1: 270/3 = 90 Marks obtained by student 2: 90, 91, 92 Average marks of student 2: 273/3 = 91 Marks obtained by student 3: 78, 85, 83 Average marks of student 3: 246/3 = 82 Marks obtained by student 4: 93, 88, 89 Average marks of student 4: 270/3 = 90 Marks obtained by student 5: 80, 86, 90.5 Average marks of student 5: 256.5/3 = = 85.5
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