Sample Problem 2 A 5.63 g sample of an impure barium chloride crystals were dissolved in water to make 100 mL aqueous solution. A 20-mL aliquot of this solution was titrated with 0.260 M AgNO3 solution using potassium chromate as indicator. What is the minimum amount of titrant needed to reach the equivalence if the sample is 96.8% pure? FW: BaCl2 = 208.23

Sample Problem 2 A 5.63 g sample of an impure barium chloride crystals were dissolved in water to make 100 mL aqueous solution. A 20-mL aliquot of this solution was titrated with 0.260 M AgNO3 solution using potassium chromate as indicator. What is the minimum amount of titrant needed to reach the equivalence if the sample is 96.8% pure? FW: BaCl2 = 208.23

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter16: Applications Of Neutralization Titrations

Section: Chapter Questions

Problem 16.20QAP

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