SAMPLE PROBLEM 2: Assume that AE are equal for each rod Reqd: Internal forces for member AB, CD, EF E Fy =0 + TAB + TcD + TEF = 15 kN B DE F Σ Mc - 0 0.5 m TAB TcD TEF E SEF OCD - SEF -0.4 m- CD-8, 0.2 m0.2 m O OCD AB EF 0.4m 0.8m 0,4 m AB V15 kN 1/2 б дв + 1/2 6 EF °CD %3D Tco(0,5) TEF (0.5) ) +1/2 AE ТАв (0,5) AE AÉ 3 2 TAB + 1/2 TEF TCD %3D 1. 2
SAMPLE PROBLEM 2: Assume that AE are equal for each rod Reqd: Internal forces for member AB, CD, EF E Fy =0 + TAB + TcD + TEF = 15 kN B DE F Σ Mc - 0 0.5 m TAB TcD TEF E SEF OCD - SEF -0.4 m- CD-8, 0.2 m0.2 m O OCD AB EF 0.4m 0.8m 0,4 m AB V15 kN 1/2 б дв + 1/2 6 EF °CD %3D Tco(0,5) TEF (0.5) ) +1/2 AE ТАв (0,5) AE AÉ 3 2 TAB + 1/2 TEF TCD %3D 1. 2
Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter11: Columns
Section: Chapter Questions
Problem 11.5.13P: Solve the preceding problem for an aluminum column with b = 6,0 in., t = 0.5 in., P = 10 kips, and E...
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