SCE // PO43- (aq) , Ag3PO4 (saturated) / Ag h a s a n I n d i c a t o r e l e c t r o d e t h a t i s a c h o o s e : l i q u i d m e m b r an e e l e ct r o d e m et a l l i c e l e c tr o d e of t he s e co n d k in d g l a ss el e c t ro d e m e t a l li c el e c t ro d e of t h e f i r st k i n d

SCE // PO43- (aq) , Ag3PO4 (saturated) / Ag h a s a n I n d i c a t o r e l e c t r o d e t h a t i s a c h o o s e : l i q u i d m e m b r an e e l e ct r o d e m et a l l i c e l e c tr o d e of t he s e co n d k in d g l a ss el e c t ro d e m e t a l li c el e c t ro d e of t h e f i r st k i n d

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter18: Electrochemistry

Section: Chapter Questions

Problem 29Q: When jump-starting a car with a dead battery, the ground jumper should be attached to a remote part...

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Ksp for Co(OH)2 is 5.92x10^-15
Détermine s'il y aura un précipité former quand on mélange 50 ml de CaCl2 0,2 M et 100 ml de Na2SO4 0,04 M? (Kps CaSO4=1,95 x 10-4)
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Pls helo ASAP. Pls help in all asked questions.
When jump-starting a car with a dead battery, the ground jumper should be attached to a remote part of the engine block. Why?
Ksp of silver phosphate Ag3PO4 = 1.3 x 10-20
For the reaction 5Ce4+ + Mn 2+ + 4H2 O → 5Ce3+ + MnO4- + 8H+ , given E0 (Ce4+ /Ce3+ ) = 1.70V,E0 (MnO4- /Mn2+ ) = 1.507V, calculate ΔG0 for this reaction ?
The standard enthalpies of formation of ClO and ClO2 are101 and 102 kJ/mol, respectively., Calculate the overallenthalpy change for each step in the following catalyticcycle: What is the enthalpy change for the overall reaction thatresults from these two steps? ClO(g) + O3(g) ---->ClO2(g) + O2(g) ClO2(g) + O(g) ---->ClO(g) + O2(g)
4- Use Hess's law to calculate the enthalpy change (in kJ/mol) of Alanine oxidation (ΔH1) using the below individual steps. C3H7NO2(s) + 3O2(g) → 5 2 CO2(g) + 5 2 H2O(l) +1 2 (H2N)C=O(s) ΔH1 =?? (H2N)C=O(s) + 3 2 O2(g)→CO2(g) + 2 H2O(l) + N2(g) ΔH2 = -632 KJ/mol C3H7NO2(s) + 15 4 O2(g) → 3 CO2(g) + 7 2 H2O(l) + 1 2 N2(g) ΔH3 = -1577 KJ/mol