See table below:Determine the maximum dry unit weight of the soil (Ans: 19.8 kN/ )Determine the optimum moisture content (Ans: 11%)Determine the degree of saturation at the optimum moisture content Gs = 2.60 (Ans: 99.30%) 5.Problem:Water ContentObservationWt. of wet Wt. of drySoil (kg) Soii (kg)The relativeis 94%. ThVol. of Mold(m³)Wt. ofCompactedsoil (kg)weights ofand Yd (mconditions1.727.90.0009450.0009450.0009450.0009450.00094526.4ctedof asionined2.027.525.3a)Con2.126.623.4com1.939.834.1b)Com1.842.234.8c)Como2.8%COMPACTIONV CURVE8.unnelThe msoil inwere16.5 krelativof thesarnein theght ofMalinev/Wwer Coneata) Determine the may. dry unit weight of thesoil.b)a)b)c)Determine the optimum moisture content.) Determine the degree of saturation at theoptimum moisture content if Gs = 2.60sed to

Answered: Image /qna-images/answer/2878a266-5263-4980-9810-7a9788e2602d.jpg

See table below: Determine the maximum dry unit weight of the soil (Ans: 19.8 kN/ ) Determine the optimum moisture content (Ans: 11%) Determine the degree of saturation at the optimum moisture content Gs = 2.60 (Ans: 99.30%)

See table below: Determine the maximum dry unit weight of the soil (Ans: 19.8 kN/ ) Determine the optimum moisture content (Ans: 11%) Determine the degree of saturation at the optimum moisture content Gs = 2.60 (Ans: 99.30%)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Wt. of pycnometer + water + soil = 707.40 g Wt. of pycnometer + water = 674.49 g Wt. of evaporating…

A: solution a) Let the wt of pyconometer + water + soil =W1wt of pyconometer + water = W2wt of…

Q: Q1: For a soil in natural state, given e =0.8 , w=24% , and Gs=2.68 (a)determine the moist unit…

Q: coefficienct of permeability, in cm/sec, round off to 7

A: Given data- Hydraulic coefficients K1 = 2 × 10-⁴ cm/s K2 = 3.2 × 10-² cm/s K3 = 4.1 ×10-⁵ cm/s…

Q: Compute the water content, void ratio, total unit weight, and dry unit weight. Weight of saturated…

Q: Calculate the dry unit weight, void ratio, water content and degree of saturation for a sample of…

Q: The moisture content and the bulk unit weight of a partially saturated silt sample were 18% and 19.6…

A: Soil, in general, is a three-phase system made up of solid, liquid, and gaseous materials. The…

Q: 100% saturated soil has a dry unit weight of 15.80 kN/m3, and its water content is 26%. Find the…

Q: A 100 cm3 soil weighed 165g when moist, then after oven drying, its weight was reduced to 130g.…

A: KINDLY NOTE, as per our company guidelines we are supposed to solve the first three sub-parts unless…

Q: 4- The moist density of a soil is 1680 kg/m³. Given wɛ = 18% and Gs = 2.73, determine: a. Dry…

A: Given that: Moist density of soil, ρt=1680 kg/m3Water content, wc=18%Gs=2.73…

Q: Figure 2 shows the dry density versus water content relationship for a fine-grained soil

Q: The moist unit weight of a soil is 16.5 KN/cu.m. If the water content is 15% and sp.gr. of soil is…

A: The given data is shown below: Moist unit weight=16.5 kN/m3Water content=15%Specific gravity=2.7

Q: A clay sample, containing its natural moisture content, weighs 0.333 N. The specific gravity of…

Q: Example 3:In the natural state, a moist soil has a volume of 0.0093 m3 and weighs 177.6 N. The oven…

A: Volume V=0.0093m3 Total weight W =177.6N Weight of solid Ws =153.6N Gs =2.71

Q: In its natural state, a moist soil has a volume of 9.35 × 10 −3 m3 and weighs 177.6 × 10−3 kN. The…

A: Moisture Content: It is the ratio of weight of water to the weight of solid (soil) present. Dry Unit…

Q: An undisturbed specimen of soil has a volume of 300 cm3 and weighs 498 g. After over drying for 24…

Q: A soil has a water content of 25% and a degree of saturation of 82%. Compute the sp.gr. of the soil…

A: Given data, Water content= w = 25% Degree of saturation= s = 82% Dry unit weight= Yd= 14.23kN/m3…

Q: A soil having natural moisture content of 28% has a liquid limit of 54% and plastic limit of 32%.…

Q: Determine the following: a.) The plasticity index of soil A. b.) The liquidity index of soil B if…

Q: A silty clay has a plastic limit of 29.0 and a plastic index of 34.0. If the clay has a liquid index…

A: It is required to determine the liquid limit. PI=LL-PL Here PI is the plasticity index, LL is the…

Q: A soil sample has a moisture content of 18%. If its dry unit weight is 14.5kN/m^3 and the specific…

Q: 1. A soil sample has a volume of 883.125 cm'. The moist soil has a mass of 1740.6 gm. When it is…

A: The water content of the soil is defined as the ratio of the weight of water to the weight of dry…

Q: water content of 17.17%. Calculate the water content (%) if the soil partially dries to a density of…

A: Given data- Bulk density(y) = 21kn/m³ Water content (w) = 17.17% Dry density (yd) = y/(1+w)…

Q: The mass of the wet sample of the soil and its container is 14.5 kg. The dry mass of the soil and…

A: Hi there! since you have posted a question with multiple sub-parts, we will solve the first three…

Q: A Sample of moist soil has a water content of 20.0% and the moist unit weight of 21.09 KN/cu.meter.…

A: Given data: w=20%γsat=21.09 kN/m3G=2.75Assume, γw=9.81 kN/m3

Q: A soil specimen having a volume of 0.012 m3 has a specific gravity of 2.60. It has a moist mass of…

A: Following is the given information Volume = 0.012 m3Specific gravity = 2.60 Moist mass= 20.6 kgDried…

Q: 5. For an undisturbed soil, the total volume is 5.1 ff3, the moist weight is 601 Ib, the dry weight…

A: As per guidelines we need to answer only first 3 subparts of question so please repost rest…

Q: In a partially saturated soil, the moisture content W% is 66.67%, the relative specific gravity of…

Q: The moist weight of 5.66 x 10^-3 m^3 of a soil is 102.3 x 10^-3 kN. The moisture content and the…

Q: 4.For a given soil, Gs = 2.74 and moist unit weight is 20.6kN/m3, and moisture content of 16.6%. a.…

Q: Assuming the water content of the soil at site is 52% and Liquid Index is 60%, calculate the…

A: there is liquid index is same as liquidity index So liquidity index is = .60

Q: A sample of 1346 grams of soil was taken from a 792 cu.cm test hole. It was then oven-dried and…

Q: 7 Undisturbed soil sample was collected from the field in steel Shelby tubes for laboratory…

Q: EX.1 A soil sample has a unit weight of (1.9gm/cc) and the water content=12%, if Gs=2.65, determine:…

A: NOTE : Since you have asked multiple questions, we will solve the first question for you. If you…

Q: For a given soil sample, it has a sp.gr. of 2.74, moisture content of 16.6% and a moist unit weight…

A: a.) The expression for void ratio is given as wG=eSe=wGS Here w is the moisture content, G is…

Q: A field compaction of the sandy loam was found to have a wet density of 2179 kg/m3 at a water…

A: Given data- Wet density (£w) = 2179kg/m³ Water content(W) =10% = 0.10 Dry density (£d) = 2000kg/m³…

Q: In a construction project, the field moist unit weight was 18.08 kN/cu.m at a moisture content of…

Q: A freshly drawn soil core of 10 cm diameter and 5 cm length weighs 700 g. On oven drying at 105°C…

A: The given data is: Weight of freshly drawn soil sample (W1) = 700 g Weight of oven dried soil (Wd) =…

Q: The hoist weight of 0.1 cubic feet of soil is 12.2 lb. If the moisture content is 12% and the…

Q: The moist unit weight of a soil is 17.79 kN/cu.m and the porosity is 0.416. If the specific gravity…

A: Note :- only part a is given and asked to find only part a. Given data, Moist unit week ght of soil…

Q: EX.2 A partially saturated soil has a volume of (6x10 m') and weight of (0.902N). The sample is…

A: volume =6×10-5m3weight = 0.902Nweigth dry =0.724NG=2.6dry unit weigth=unit weigth of soil1+ωω= water…

Q: Determine the maximum dry unit weight of soil Determine the optimum moisture content If the dry unit…

Q: An undisturbed sample of clayey soil is found to have a wet weight of 285 N, a dry weight of 250 N,…

A: Given- wet weight-Wwet=285 Ndry weight-Wdry=250 Ntotal volumeVT=14×103 cm3G=2.70 It is needed to…

Q: The weight of a sample of partially saturated soil 600 g with a volume of 365 cm3 and after drying…

Q: For a given soil, the following are given: Gs = 2.63; moist unit weight = 17.15 kN/m3, and moisture…

Q: Find degree of saturation if water content is 15% , specific gravity of soil solid 2.67 , Void ratio…

A: Water content = 15% W = 0.15 Specific Gravity, G = 2.67 Void Ratio, e = 0.5 We…

Q: Determine the seepage velocity, in cm/min, if the porosity of soil is 0.30

Q: For a given soil, the following are given: Gs = 2.68; moist unit weight = 17.4 kN/m3, and moisture…

Q: The hydraulic conductivity of a clayey soil is 4 x 10^-7 cm/sec. The viscosity of water at 25 deg C…

A: Given data, k = 4×10-7 cm/sec γ25 = 0.0911×10-4 g.sec/sq.cm γw = 1 g/cm3

Q: Determine the maximum dry unit weight of compaction Determine the optimum moisture content Determine…

Q: You were tasked to draw the Soil-Water Characteristic Curve (SWCC) of four types of soil: sand,…

A: Soil water characteristic curve (SWCC) is widely known as the relationship between matric suction…

Question

See table below:

Determine the maximum dry unit weight of the soil (Ans: 19.8 kN/ )
Determine the optimum moisture content (Ans: 11%)
Determine the degree of saturation at the optimum moisture content Gs = 2.60 (Ans: 99.30%)

5.
Problem:
Water Content
Observation
Wt. of wet Wt. of dry
Soil (kg) Soii (kg)
The relative
is 94%. Th
Vol. of Mold
(m³)
Wt. of
Compacted
soil (kg)
weights of
and Yd (m
conditions
1.7
27.9
0.000945
0.000945
0.000945
0.000945
0.000945
26.4
cted
of a
sion
ined
2.0
27.5
25.3
a)
Con
2.1
26.6
23.4
com
1.9
39.8
34.1
b)
Com
1.8
42.2
34.8
c)
Co
mo
2.8%
COMPACTIONV CURVE
8.
unnel
The m
soil in
were
16.5 k
relativ
of the
sarne
in the
ght of
Malinev/Wwer Coneat
a) Determine the may. dry unit weight of the
soil.
b)
a)
b)
c)
Determine the optimum moisture content.
) Determine the degree of saturation at the
optimum moisture content if Gs = 2.60
sed to

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Similar questions

Follow instructions, box your answers and put a proper units. ANSWER: (a) 1, -4.9 (b) 13/9 (c) 5/9, -4/9 (d) 20/9, -16/9 1.) (a) 9, -4 (b) 13 (c) 5, -4 (d) 20 kN.m, -16 kN.m 2.) (a) 27, -3.56 (b) 56.33 (c) 8.33, -10.67 (d) 60 kN.m, -21.33 kN.m
Redo Problem 10.1 with the following:Db = 1.75 m γc = 17.8 kN/m3Ds = 1 m γs = 18.2 kN/m3L1 = 6.25 m Φ' = 32°L2 = 2.5 m cu = 32 kN/m2Factor of safety = 4
Solve it plz early ok
A steep rectangular channel is to carry flow rate of 1.90 m3/s wirh a slope of 0.01 and roughness coefficient of 0.011, for a minimum area of the material to use, compute: Depth if the channel in m 0.15 1.51 1.15 0.51 Width of the channel in m .30 1.02 3.02 2.30 Area of the steel material to be used if the channel is 3m 4.56 0.52 0.45 6.12
SHOW COMPLETE SOLUTION PLS VALUE:Y = 53
SITUATION B: Prepare and complete the profile level notes for the information shown and perform the customary arithmetic check. What is the difference in elevation between TP1 and TP2? STA BS HI FS IFS ELEV BM1 2.32 328.70 1 1.7 2 2.2 3 1.2 4 0.9 TP1 2.77 3.43 5 2.2 6 3.7 7 1.6 TP2 2.22 3.06 8 2.8 9 3.6 10 2.0 11 1.1 BM2 2.45
Civil, Rquired an right answer In a furrow irrigation system, the length of the furrow is 200 metres, the advance time is 240 minutes, and the advance equation is x = p * t_r r, where "p" and "r" are 8 and 0.7, respectively. The separations of the chosen stations from the furrow's starting are 40, 80, 120, 160, and 200 metres. (Using t as the minute and Z as the millimetre) Z = 5t 0.56 is the integrated infiltration equation. Establish the possibility for infiltration and the depth of water in the soil at each station. Determine deep percolation and runoff if the width of the furrow is 0.8 metres, the input discharge into the furrow is 1.5 litres per second, and the root depth is 90 millimetres.
Follow instructions. Box your answers and don't forget your proper units. ANSWER: (a) -1 (b) 1 (c) 0.4, -0.7 (d) -4.0 (e) 2.1, -1.2 1.) (a) -4 (b) 4 (c) 1.6, -2.8 (d) -16 kN.m (e) 8.4, -4.8 kN.m 2.) (a) -10 (b) 14.5 (c) 3.125, -6.125 (d) -20 kN.m (e) 26.25 kN.m, -6 kN.m
Solve All asap ok
Trials Angle (deg) R (m) Y max (m) Time (s) 1 25° 25.99 m 1.59 s 2 30° 28.60 m 1.83 s 3 45° 33.03 m 2.60 s 4 60° 28.60 m 3.18 s 5 65° 25.30 m 3.33 s 6 90° 0 m 3.67 s Solve for Ymax (m)
C is roughness coefficient. Hazen Williams Formula: H?=10.67??^1.85/?^1.85?^4.87
a = 4.5 m b = 33.0 kN/m c = 13 kN