A 100-kg box is towed to move horizontally from rest by a constant force P=200 N. The kinetic friction is μk =0.1. The angle of the force P is θ=30° with respect to the horizontal direction.  The acceleration due to gravity is g=9.81 m/s2.

International Edition---engineering Mechanics: Statics, 4th Edition
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ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
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Chapter7: Dry Friction
Section: Chapter Questions
Problem 7.48P: Find the smallest distance d for which the hook will remain at rest when acted on by the force P....
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A 100-kg box is towed to move horizontally from rest by a constant force P=200 N. The kinetic friction is μk =0.1. The angle of the force P is θ=30° with respect to the horizontal direction.  The acceleration due to gravity is g=9.81 m/s2

 

(3) Select the expression of the friction force F. ___________




 
 

  A.

F=μN

  B.

F=μP

  C.

F=μmg

  D.

F=0

A 100-kg box is towed to move horizontally from rest by a constant force P-200 N. The
kinetic friction is μ =0.1. The angle of the force P is 8-30° with respect to the horizontal
direction. The acceleration due to gravity is g=9.81 m/s²
(3) Select the expression of the friction force F.
O A F=UN
O B. F=uP
O C.F=umg
O D.F=0
P
Transcribed Image Text:A 100-kg box is towed to move horizontally from rest by a constant force P-200 N. The kinetic friction is μ =0.1. The angle of the force P is 8-30° with respect to the horizontal direction. The acceleration due to gravity is g=9.81 m/s² (3) Select the expression of the friction force F. O A F=UN O B. F=uP O C.F=umg O D.F=0 P
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