QuestionSelect the graph of the related function. Then use the graph to solve the quadraticequation.4040323224241616(5, 10)(-4, 1)| (5, 10)(4, 1)(-5, 9)8-(-4,0)(5, 9)(4, 0).A-16-16(0,-15)(0,-16)-24-24-32-3240-40-20 -16 -12 -84.12 16 20-20 -16 -12-844 8 12 16 20404032322424(О, 16)1616-(-4, 0)(-5, -9),+(4, 0)–(5, -9)(-5, 8)(-4,-1)(5, 8).(4, -1)-8-8-16-16(0,-17)-24-24-32-32-4040-20-15 -12 -8 44812 16 20-20 -15 -12 -848.12 16 20Ouestio n 1of7Next Ouestion -16-16(0, -15)(0, -16)-24-24-32-32-4040-20 -16 -12 -848.12 16 20-20 -16 -12 -812 16 204 84040323224(0, 16)241616(-5, 8)<(-4, -1)(5, 8)(4, -1)8.0<(-4, 0)(-5, -9),+(4,0)-D(5,-9)--8-16-16(0, -17)-24-24-32-324040-20 -16 -12 8 4 04.8.12 16 20-20 -16 -12 -8-44.12 16 20The solutions of the equation x2- 29 = -13 are x =and x =一

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Answered: Select the graph of the related…

Select the graph of the related function. Then use the graph to solve the quadraticequation. 40 40 32 32 24 24 16 16 (-5, 10) (5, 10) (-5, 9) (5, 9). 8

College Algebra

10th Edition

ISBN:9781337282291

Author:Ron Larson

Publisher:Ron Larson

Chapter3: Polynomial Functions

Section3.1: Quadratic Functions And Models

Problem 79E

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Concept explainers

Maximization

Have you ever seen a bridge in the shape of a parabola? Where is its maximum on the bridge? The maximum of that bridge is the highest point on that bridge. The process of finding the maximum of the bridge here is called the maximization.

Question

-16
-16
(0, -15)
(0, -16)
-24
-24
-32
-32
-40
40
-20 -16 -12 -8
4
8.
12 16 20
-20 -16 -12 -8
12 16 20
4 8
40
40
32
32
24
(0, 16)
24
16
16
(-5, 8)
<(-4, -1)
(5, 8)
(4, -1)
8.
0<(-4, 0)
(-5, -9),
+(4,0)-
D
(5,-9)-
-8
-16
-16
(0, -17)
-24
-24
-32
-32
40
40
-20 -16 -12 8 4 0
4.
8.
12 16 20
-20 -16 -12 -8
-4
4.
12 16 20
The solutions of the equation x2- 29 = -13 are x =
and x =
一

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