Semiconductor Physics /Microelectronics: Why is the voltage drop across a PN junction expressed as V = (1/e0)*x_p*N_a*q*(W/2)? Can you derive it?
Semiconductor Physics /Microelectronics: Why is the voltage drop across a PN junction expressed as V = (1/e0)*x_p*N_a*q*(W/2)? Can you derive it?
Modern Physics
3rd Edition
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Chapter12: The Solid State
Section: Chapter Questions
Problem 16P
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Semiconductor Physics /Microelectronics: Why is the voltage drop across a PN junction expressed as V = (1/e0)*x_p*N_a*q*(W/2)? Can you derive it?
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I'm a little confused here. Why is E = (1/e0) *integral row dx? Isn't Integral(E dA) = Qenc/e0 = integral (row dV)/e0. I'm not sure if what you wrote follows from Gauss' Law. Where did you expression from for the junction potentional? I don't see it my book or anywhere else.
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