Set-up the integral to calculate the area of a region bounded by x-y=3 and y=x2-6x+9? отг А 0 В С D гр у+3 y2-6y +9 гр 0 у-3 y²-6y +9 dx dy x² - 6x +9 0 x-3 -3 SS³ 3 x² - 6x +9 dx dy dy dx dy dx

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A: I am attaching image so that you understand each and every step.

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A: I am attaching image so that you understand each and every step.