Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. e-4-3x, (0, 1) The equation ex 4 - 3x is equivalent to the equation f(x) = ex- 4 + 3x = 0. f(x) is continuous on the interval [0, 1], f(0) = there is a root of the equation ex 4-3x, in the interval (0, 1). and f(1) = Since ---Select--- < 0 <--Select-- there is a number c in (0, 1) such that f(c) = 0 by the Intermediate Value Theorem. Thus

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Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval.
ex = 43x, (0, 1)
The equation e* = 4 - 3x is equivalent to the equation f(x) = e* - 4 + 3x = 0. f(x) is continuous on the interval [0, 1], f(0) =
there is a root of the equation ex = 4 - 3x, in the interval (0, 1).
, and f(1) =
. Since
-Select---
< 0<---Select---
1
there is a number c in (0, 1) such that f(c) = 0 by the Intermediate Value Theorem. Thus,
Transcribed Image Text:Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. ex = 43x, (0, 1) The equation e* = 4 - 3x is equivalent to the equation f(x) = e* - 4 + 3x = 0. f(x) is continuous on the interval [0, 1], f(0) = there is a root of the equation ex = 4 - 3x, in the interval (0, 1). , and f(1) = . Since -Select--- < 0<---Select--- 1 there is a number c in (0, 1) such that f(c) = 0 by the Intermediate Value Theorem. Thus,
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