Show me the determine red and all information is here Let w2n-1 = Un, W2n-2 = Vn, 22n–1 = Xn and z2n-2 = Yn, implies thatVn+1 – ko Un – kio Vn = µ,(11)Un+1 – kį Vn+1 – kị Un = µ,andYn+1 – Vo Xn – v Yn = €,(12)Xn+1 – Vị Yn+1 – V1 Xn = €.It is observe that, the equations (11) and (12) are system of linear non-homogeneous differenceequations with constants coefficients. First, we solve the system in (11). Thus, consider (11) is(E – ko) Vn – ko Un(13)(E – ki) Un – ki E V,(14)where E = A + 1, is the shift operator. Multiplying (13) and (14) by (E – k1) and ko,respectively,(E – k1) (E – ko) Vn – (E – k1) ko Un(E – ki) µ,(15)ko (E – k1) Un – ko ki E V,ko fH.(16)Thus, the combination of (15) and (16) is(E²(ko + ki + ko ki) E + ko k1) Vn(1 – k1 + ko) µ,(17)(E? – o E + ko ki) Vn = (1 – k1 + ko) µ,where ø = ko + k1 + ko k1. Clearly, (17) is linear difference equations from order two and it iseasy to obtain the solution,nø + Vo? – 4 ko kı6² – 4 ko k'1(1– kị + ko1 – ko – k1.Ф —-Vn= A+ B(18)2since A and B are constants. By Substituting (18) in (13), we give1Un = Ako- 4 ko k1ф +14 ko ki226² – 4 ko k10² – 4 ko kiФ —+ B1(19)2(G-)(1– k1 + ko+1 — kо — ki,H.ko6. Zn-hWn-pp=1Wn-pZn-hh=0h=1+ €,(4)p=0+ µ and zn+1Wn+1Wn - uZn - €where u and e are arbitrary positive real numbers with initial conditions w; and z; for i =-2, –1,0.

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We need to find part in red.