Show that if there is an Archimedean solid that has faces that are regular pentagons and equilateral triangles, and where four faces meet at each vertex, then there must be eight more triangles than pentagons.

Show that if there is an Archimedean solid that has faces that are regular pentagons and equilateral triangles, and where four faces meet at each vertex, then there must be eight more triangles than pentagons.

Name: Show that if there is an Archimedean solid that has faces that are re
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Description: Show that if there is an Archimedean solid that has faces that are regular pentagonsand equilateral triangles, and where four faces meet at each vertex, then there mustbe eight more triangles than pentagons.1.

Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

Chapter5: Similar Triangles

Section5.2: Similar Polygons

Problem 3E: a Are any two regular pentagons similar? b Are any two equiangular pentagons similar?

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