show that Language Letan bn cnnzo3is not a conteit free.
Q: e closure under union to show that the language {amb" : m #n} is context-free.
A: Using closure under union to Proved that gives language is CFL
Q: Ll is a regular language with some alphabet E, and if strings in Llare replaced with other strings,…
A: The Answer is in below Step
Q: a)Prove that the following language is not regular. L = {w.w': w∈ {a, b}*| w' is obtained by…
A: A language that cannot be defined by a regular expression is a non regular language or an irregular…
Q: How to prove that the language {am bn cp | m,n,p are greater than or equal to zero and m != n and…
A: We are going to prove that the language {am bn cp | m,n,p are greater than or equal to zero and m !=…
Q: Let L = {w#w | w ∈ {a, b}*} be a language. Use the pumping lemma for regular languages to prove that…
A: L = {w#w| w∈ {a, b}*} string generated by this languageare aaab#aaab, babb#babb proof: If possible…
Q: Give pushdown automata that recognize the following language. L = {a bi ck | i,j,k ≥ 0 and i + j = k…
A:
Q: Use the Pumping Lemma to prove that the language L= (a"b2n: n >= 0} is NOT context free.
A:
Q: Construct an npda that accepts the regular language L (aaa*b).
A: construct an nondeterministic push-down automata L(aaa*b)
Q: Prove that the language L2={a^i b^k c^(2k) | i, k >= 0} is not regular language with the pumping…
A: The given language is expanded as L1= {aa , aabbcc , abbcccc , ....... }Now, we are going to prove…
Q: Prove that there is no language L such that L* = a*b* (use proof by contradiction).
A: The best way to show that L isn't a normal language: PresumingSuppose L is a consistent speech, then…
Q: 4 I Can't Decide Prove that the following language is undecidable: SU BCFG = {(G1, G2) | G1 and G2…
A: Proved the given program is undecidable
Q: show that this language is not regular through the pumping lemma L = {w= {a,b,c}* #(a)=#(b) oder…
A: Pumping Lemma is used to test whether the given language is regular or not. It is negativity test,…
Q: Given S = {x, y, z}. Prove following language L is decidable: L = {u E S * : u has the same number…
A: We are given a language and we have to prove that the given language is decidable. Please refer to…
Q: Question 2 Let L be the language L-(anbmen | (3n+n)>m) over the alphabet Z-(a.b.c). Prove that Lis…
A: Given Language : L = {a3nbmcn | 3n+n>m} Alphabet Set = {a,b,c} String of Language : The…
Q: write down the hegular expre88ion of the hegular language L= W SuChtHhat w stehts with I Cnd atleast…
A: The language L will look like L={100, 100000,10010,.......} The minimum acceptable string is 100 as…
Q: Find regular expressions over {0, 1} that determine the following languages: (i) {u | u…
A: Give:- Two languages and alphabets = {0,1}. We have to find :- 1. Regular expressions for both…
Q: Build a PM that accepts the language of all words that have an a as the middle letter: (These words…
A: 1)The Language that accepts all the words that have an a as the middle letter is: waw' where w and…
Q: Construct NPDAs that accept the following regular languages. (a) L1 = L (aaa*b). (b) L2 = L…
A: (a) L1=L(aaa*b) solution: The npda M=(K,∑,T,∆,s,F), where K=q0,q1,q2,f,∑{a,b}, F={f}, and ∆ as the…
Q: Given, the language L={awa|wE{a,b}*}. Show that the language L2={aw1aaw2a|w1,w2E{a,b}*} is regular.
A: Answer: I have given answered in the handwritten format in brief explanation
Q: b. Use the Pumping Lemma to show that the language is not regular.. L = {0*10° |i > 1}
A: Pumping lemma for regular languages: if a language L is regular, then there exist integer n, such…
Q: Consider the languages below. For each, make a conjecture whether or not it is regular. Then prove…
A: The given language L = {anbl : n/l is an integer} is not regular language because a DFA cannot be…
Q: Give a regular expression for the smallest language Lover Σ = {a,b,c} such that EEL • aa EL Vr E L,…
A: A regular expression is a character sequence that describes a text search pattern. String-searching…
Q: Prove the language L = { |M accepts w in less than 10 steps } is Turing decidable. Note: solution in…
A: A language is Turing decidable, if some Turing machine decides it. What does decides mean ? A…
Q: (a) Find an nfa with three states that accepts the language L = {an : n ≥ 1} ∪ {bmak : m ≥ 0, k ≥ 0}
A: Graphical representation of NFA:The starting state is denoted by an empty incoming arc, the vertices…
Q: 2. Prove that the following language is not context free using the pumping lemma for context free…
A: Solution for following question - Pumping Lemma for CFL states that for any Context Free Language…
Q: write wuthab if ststment to oaladatey where Matlab ge Sin(x) if ax is in [o, amd yoo
A: Here y is a dependent variable, that is its value depends on the value of the independent variable…
Q: 3. Give a Finite Automaton of the language, over alphabet {a, b}, of strings that end with b.
A: Answer of the given question : Here is the deterministic finite automata for the given language.…
Q: Create a Deterministic Finite Automaton (DFA) for the language L that is defined over the input…
A: - We have to examine the DFA according to the conditions and remake it if it's wrong.
Q: Consider the language L = {a^b³ct | r, s, t € N and t ≤r× s} Problem 3 Use the pumping lemma to…
A: Pumping lemma for CFL is used to prove the language is not cfl using some valid string s. Never use…
Q: Q. Construct a (Deterministic finite automaton) DFA that accepts the language given below which is…
A: Design a FA with ∑ = {0, 1} accepts at least one 1 at most one 0
Q: Construct a finite automaton on the alphabet {s, t, u} that recognizes the language M, M = {x | such…
A: We are going to construct a finite automata which will accept strings which starts with st. Please…
Q: consider the language L = {a^f b^g|f<g} on albhabet E = {a,b}. Show that L is not reguar. %3D
A: The answer is
Q: 4. Find do that accept the following languages. (a) L (aa* + aba*b*). nfa (b) L (ab (a + ab)* (a+…
A: Non-deterministic finite automata of the given regular expression
Q: Design a deterministic finite-state automaton (DFA) that accepts exactly the strings over the…
A: atleast two R atmost one T and E comes after S
Q: ALL = { | L(T) = \Sigma*} where is the string encoding of the TM T.
A: ALL = { <T> | L(T) = \Sigma*} where <T> is the string encoding of the TM T.shown that…
Q: construct an NFA that realizes the language L over the alphabet {a, b, c} that consists of all…
A: Here is the NFA about the string given:
Q: Show that the language L {a' b"li>0} is not regular.
A: Given language is, L={aib2i | i>0} Regular languages are the languages which are finite and these…
Q: a) Prove that the language L is decidable where L = {(G)|G is a CFG which generates a string with…
A: Answer
Q: No need to apply pumping lemma in this Queshon Demonstrate or that ; prove L= {w e {a,b,c,d}*…
A:
Q: a) Construct a push-down automaton that accepts the language L = {a'b'c*[i = j_or i =k for i> 0}.
A: The answer is
Q: Prove that the following language L is not regular: L = {0"1™ | n and m are positive integers and m>…
A: Let, F be the language 0*. Let, x and y be arbitrary strings in F. Then x=0i and y=0j for some…
Q: consider the language L = {a^fb^g|f<g} on albhabet E = {a,b}. Show that L is not reguar. %3D
A: The answer is
Q: Exercise4: Consider the language L on = {0,1} with L= {w such that w starts with 1and ends with 00}…
A:
Q: proof with pumping lemma A={ aibjck | i,j,k ≥0,i=j veya j=k} is nonregular language
A: proof with pumping lemma A={ aibjck | i,j,k ≥0,i=j veya j=k} is nonregular language
Q: Let A be a language such that A ≤m PCP and ETM ≤m A. What can you say about A? Briefly explain your…
A: ans is given beolw step
Q: QUESTION 1 Let L be the language L={ aPb9cd> I p#q and qer} over the alphabet E={a,b,c,d}. Prove…
A: By pumping lemma to proved that given language is not regular
Q: Give pushdown automata that recognize the following language. L = {a' bi ck | i.j,k 2 0 and i + j =…
A: Pushdown automata of the language
Q: Using pumping lemma prove that the language L = { aibj | i < j < 2i } is not regular.
A: Answer: Using Pumping Lemma prove that the language L= { aibj | i < j < 2i } is Not Regular.
Q: (2) Let r=(b*a* ba)+ (ab + ba)* b be a regular expression (a) find an nfa to accept the regular…
A: The answer to the following question:-
Q: Let language A= {w | w can be written ajbk where k is a multiple of j.}. a. Show that Ais not…
A: Given: Let language A= {w | w can be written ajbk where k is a multiple of j.}. a. Show that Ais not…
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- نقطة واحدة Let A = {a; b; c; d} and R= {(a; a); (b; c); (c; b); (d; d)} then R is Transitive Equivalent not transitivetonquage accepting any no.fa's } prite a P.E for the and b's over, & = {a,b?class A Q5: Correct the following code fragment and what will be the final results of the variable a and b { protected int x1,y1,z; public: A(a, b,c):x1(a+2),y1(b-1),z(c+2) { for(i=0; i<5;i++) x1++; y1++;z++;}}; class B { protected: int x,y; public: B(a,b):x(a+1),y(b+2) { for(i=0; i<5;i++) x+=2; y+=1;}}; class D:public B, virtual public A { private: int a,b; public: D(k,m,n): a(k+n), B(k,m),b(n+2),A(k,m,n) { a=a+1;b=b+1;}}; int main() {D ob(4,2,5);}
- #include <iostream> using namespace std;struct Triple{int row, col, value;}; class Matrix; class MatrixNode{friend class Matrix;friend istream& operator>>(istream&, Matrix&);private:MatrixNode *down, *right;bool head;union{MatrixNode *next;Triple triple;};MatrixNode(bool, Triple*);}; MatrixNode::MatrixNode(bool b, Triple *t){head = b;if (b){right = down = this;}else triple = *t;};class Matrix{friend istream& operator>>(istream&, Matrix&);public:~Matrix();MatrixNode*private:MatrixNode *headnode;}; Matrix::~Matrix(){// Return all nodes to the av list, which is a chain linked// via the right field.// av is a static variable pointing to the first of the av list.if (!headnode )return; // no nodes to deleteMatrixNode *x = headnode->right; headnode->right = av;av = headnode; // return headnode while (x != headnode) { // return nodes by rowsMatrixNode *y = x->right;x->right = av;av = y;x = x->next; // next row}headnode = 0;} istream&…in c++ i have this struct struct Student { string firstName, lastName; int pointTotal; }; void printStudent(const Student & s) { cout << s.pointTotal << "\t" << s.lastName << ", " << s.firstName << endl;}void printAll(Student students[], int numStudents) { for (int i = 0; i < numStudents; i++) printStudent(students[i]); cout << endl;}int main() { const int NUMSTUDENTS = 7; Student students[NUMSTUDENTS] = { {"Brian", "Jones", 45},{"Edith", "Piaf", 45},{"Jacques", "Brel", 64},{"Anna", "Brel", 64}, {"Carmen", "Jones", 45} , {"Carmen", "Brel", 64}, {"Antoine", "Piaf", 45}, {"Pascal", "Piaf", 64} }; printAll(students, NUMSTUDENTS); sortByPointTotal(students, NUMSTUDENTS); printAll(students, NUMSTUDENTS); return 0;} i need to make a function that uses bubble sort(coded from scratch), but modify it so that the comparison for out-of-order elements takes into account all three fields:…#include <iostream> using namespace std;struct Triple{int row, col, value;}; class Matrix; class MatrixNode{friend class Matrix;friend istream& operator>>(istream&, Matrix&);private:MatrixNode *down, *right;bool head;union{MatrixNode *next;Triple triple;};MatrixNode(bool, Triple*);}; MatrixNode::MatrixNode(bool b, Triple *t){head = b;if (b){right = down = this;}else triple = *t;};class Matrix{friend istream& operator>>(istream&, Matrix&);public:~Matrix();MatrixNode*private:MatrixNode *headnode;}; Matrix::~Matrix(){// Return all nodes to the av list, which is a chain linked// via the right field.// av is a static variable pointing to the first of the av list.if (!headnode )return; // no nodes to deleteMatrixNode *x = headnode->right; headnode->right = av;av = headnode; // return headnode while (x != headnode) { // return nodes by rowsMatrixNode *y = x->right;x->right = av;av = y;x = x->next; // next row}headnode = 0;} istream&…
- Design a struct with following members: p_num_lots, int* type pa_lots, int [] type (dynamically allocated) Implement following methods: parameterized constructor which takes an int for num of lots copy constructor copy assignment operator destructor1. Draw a dfa of L/L2 for L1 {a"b" : n > 1, m 2 0}U {ba} L2 = {b"aa : m 2 0}Computer Science Write in Javascript please and use high order functions liek map or filter or reduce let obj = [ { mode: "hot" }, { temp: "low" }, { mode: "cold } ] I want to create a function that get object by key such as: myFunc("mode"); returns { mode: "hot" } next call of myFunc("mode") returns { mode: "cold1- what is the language that describe Regular Expression of a* (ba*ba*)*? 2- if A be the set of integer numbers from (0 to 9) , and B be the set of odd integer numbers between ( 0 and 9) . what will be the Formal Description for themin C++ make sure input for entering phone # is availible Given a long long integer representing a 10-digit phone number, write a function to segment this number into a three-digit area code a three-digit prefix a four-digit line number Ex: If the input is: 8005551212 It will be segmented into: 800, 555, and 1212. Your code needs to 1. declare a new datatype struct StructuredPhoneNumber{ std::string areaCode="000"; //3 digits std::string prefix="000"; //3 digits std::string lineNo="0000"; // 4 digits}; 2. Use the following function prototype to implement your algorithm: //converts a phone number from a 10-digit long long to {area code, prefix, lineNo}/returns a StructuredPhoneNumber object {"000", "000", "0000"} if the input number is negative or does not contain 10 digits. StructuredPhoneNumber phoneNumBreakdown(long long phoneNum_ll); 3. include three unit tests test1( ), test2(), and test3(), each of which returns true if phoneNumBreakdown( ) correctly…SEE MORE QUESTIONS
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