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struct ID { int x; int y; }; struct name { ID r; }; int main() { name a[2]; for (int i=0;i<2;i++) { a[i].r.x=i; a[i].r.y=i+1; } for (int i=0;i<2;i++) cout<

struct ID { int x; int y; }; struct name { ID r; }; int main() { name a[2]; for (int i=0;i<2;i++) { a[i].r.x=i; a[i].r.y=i+1; } for (int i=0;i<2;i++) cout<

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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struct ID { int x; int y; }; struct name { ID r; }; int main() { name a[2]; for (int i=0;i<2;i++) { a[i).r.x=i; a[i].r.y=i+1; } for(int i=0;i<2;i++) cout<<a[i].r.x+a[i].r.y; return 0; } Answer:
Transcribed Image Text:struct ID { int x; int y; }; struct name { ID r; }; int main() { name a[2]; for (int i=0;i<2;i++) { a[i).r.x=i; a[i].r.y=i+1; } for(int i=0;i<2;i++) cout<<a[i].r.x+a[i].r.y; return 0; } Answer:
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