Show the pH calculation process when 24.00, 25.0, 30.00 mL of 0.100 M NaOH are added to 50.00-mL 0.0500 M HCl. Effect of Concentration in the Equivalence-Point RegionpHVolume of50.00 mL of 0.0500 M HCI50.00 ml. of 0.000500 M HCIN2OH, mLwith 0.100 M NaOHwith 0.00100 M N2OH0.001.303.3010,001.603.6020.002.154.1524.(XI2.874.873.875.877.0024.9025.007.0025.1010.128.129.1226.0011.1230.0011.809.80

HCl and NaOH react with each other to form water and NaCl salt. In any aqueous solution the…

Answered: Show the pH calculation process when…

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Show the pH calculation process when 24.00, 25.0, 30.00 mL of 0.100 M NaOH are added to 50.00-mL 0.0500 M HCl.

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.10QAP

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

Show the pH calculation process when 24.00, 25.0, 30.00 mL of 0.100 M NaOH are added to 50.00-mL 0.0500 M HCl.

Effect of Concentration in the Equivalence-Point Region
pH
Volume of
50.00 mL of 0.0500 M HCI
50.00 ml. of 0.000500 M HCI
N2OH, mL
with 0.100 M NaOH
with 0.00100 M N2OH
0.00
1.30
3.30
10,00
1.60
3.60
20.00
2.15
4.15
24.(XI
2.87
4.87
3.87
5.87
7.00
24.90
25.00
7.00
25.10
10.12
8.12
9.12
26.00
11.12
30.00
11.80
9.80

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