Shuster (1991) describes an case involving the sale of cc packets of cocaine, of which actually be cocaine. The po as drug dealers, sold the pa before they could be tested (a) If the original 496 packet noncocaine, show that noncocaine packets, wh buying cocaine, is

College Algebra
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ISBN:9781337282291
Author:Ron Larson
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Chapter8: Sequences, Series,and Probability
Section8.7: Probability
Problem 11ECP: A manufacturer has determined that a machine averages one faulty unit for every 500 it produces....
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In addition to Diaconis allU MUSTEIICI
dences.
3.10 Shuster (1991) describes a number of probability calculations that he did for a court
case involving the sale of cocaine. A Florida police department seized 496 suspected
packets of cocaine, of which four were randomly selected and tested and found to
actually be cocaine. The police then chose two more packets at random and, posing
as drug dealers, sold the packets to the defendant. These last two packets were lost
before they could be tested to verify that they were, indeed, cocaine.
(a) If the original 496 packets were composed of N packets of cocaine and M = 496-N
noncocaine, show that the probability of selecting 4 cocaine packets and then 2
noncocaine packets, which is the probability that the defendant is innocent of
buying cocaine, is
N
4
N+ M
N + M -4
4
(b) Maximizing (in M and N) the probability in part (a) maximizes the defendant's
"innocence probability". Show that this probability is .022, attained at M = 165
and N = 331.
either the binomial or the
Transcribed Image Text:In addition to Diaconis allU MUSTEIICI dences. 3.10 Shuster (1991) describes a number of probability calculations that he did for a court case involving the sale of cocaine. A Florida police department seized 496 suspected packets of cocaine, of which four were randomly selected and tested and found to actually be cocaine. The police then chose two more packets at random and, posing as drug dealers, sold the packets to the defendant. These last two packets were lost before they could be tested to verify that they were, indeed, cocaine. (a) If the original 496 packets were composed of N packets of cocaine and M = 496-N noncocaine, show that the probability of selecting 4 cocaine packets and then 2 noncocaine packets, which is the probability that the defendant is innocent of buying cocaine, is N 4 N+ M N + M -4 4 (b) Maximizing (in M and N) the probability in part (a) maximizes the defendant's "innocence probability". Show that this probability is .022, attained at M = 165 and N = 331. either the binomial or the
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