"Simon Says" is a memory game where "Simon" outputs a sequence of 10 characters (R, G, B, Y) and the user must repeat the sequence. Create a for loop that compares each character of the two strings. For each matching character, add one point to user_score. Upon a mismatch, end the loop. Sample output with inputs: 'RRGBRYYBGY' 'RRGBBRYBGY' User score: 4 1 user_score = 0 2 simon_pattern = input() 3 user_pattern = input() 4 5 '' Your solution goes here ''" 6 7 print('User score:', user_score)

"Simon Says" is a memory game where "Simon" outputs a sequence of 10 characters (R, G, B, Y) and the user must repeat the sequence. Create a for loop that compares each character of the two strings. For each matching character, add one point to user_score. Upon a mismatch, end the loop. Sample output with inputs: 'RRGBRYYBGY' 'RRGBBRYBGY' User score: 4 1 user_score = 0 2 simon_pattern = input() 3 user_pattern = input() 4 5 '' Your solution goes here ''" 6 7 print('User score:', user_score)

Microsoft Visual C#

7th Edition

ISBN:9781337102100

Author:Joyce, Farrell.

Publisher:Joyce, Farrell.

Chapter5: Looping

Section: Chapter Questions

Problem 13E

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"Simon Says" is a memory game where "Simon" outputs a sequence of 10 characters (R, G, B, Y) and the user must repeat the sequence. Create a for loop that compares each character of the two strings. For each matching character, add one point to user_score. Upon a mismatch, end the loop.Sample output with inputs: 'RRGBRYYBGY' 'RRGBBRYBGY' User score: 4 user_score = 0simon_pattern = input()user_pattern = input() ''' Your solution goes here ''' print('User score:', user_score)
CHALLENGE ACTIVITY 5.10.2: Simon says. "Simon Says" is a memory game where "Simon" outputs a sequence of 10 characters (R, G, B, Y) and the user must repeat the sequence. Create a for loop that compares each character of the two strings. For each matching character, add one point to user_score. Upon a mismatch, end the loop.Sample output with inputs: 'RRGBRYYBGY' 'RRGBBRYBGY' User score: 4 Use Python, please.
"Simon Says" is a memory game where "Simon" outputs a sequence of 10 characters (R, G, B, Y) and the user must repeat the sequence. Create a for loop that compares the two strings starting from index 0. For each match, add one point to userScore. Upon a mismatch, exit the loop using a break statement. Assume simonPattern and userPattern are always the same length. Ex: The following patterns yield a userScore of 4:simonPattern: RRGBRYYBGY userPattern: RRGBBRYBGY #include <iostream>#include <string>using namespace std; int main() { string simonPattern; string userPattern; int userScore; int i; userScore = 0; cin >> simonPattern; cin >> userPattern; /* Your solution goes here */ cout << "userScore: " << userScore << endl; return 0;}
"Simon Says" is a memory game where "Simon" outputs a sequence of 10 characters (R, G, B, Y) and the user must repeat the sequence. Create a for loop that compares the two strings starting from index 0. For each match, add one point to userScore. Upon a mismatch, exit the loop using a break statement. Assume simonPattern and userPattern are always the same length. Ex: The following patterns yield a userScore of 4: simonPattern: RRGBRYYBGY userPattern: RRGBBRYBGY import java.util.Scanner; public class SimonSays {public static void main (String [] args) {Scanner scnr = new Scanner(System.in);String simonPattern;String userPattern;int userScore;int i; userScore = 0; simonPattern = scnr.next();userPattern = scnr.next(); /* Your solution goes here */ System.out.println("userScore: " + userScore); return;}}
"Simon Says" is a memory game where "Simon" outputs a sequence of 10 characters (R, G, B, Y) and the user must repeat the sequence. Create a for loop that compares the two strings starting from index 0. For each match, add one point to userScore. Upon a mismatch, exit the loop using a break statement. Assume simonPattern and userPattern are always the same length. Ex: The following patterns yield a userScore of 4: simonPattern: RRGBRYYBGY userPattern: RRGBBRYBGY #include <iostream>#include <string>using namespace std; int main() {string simonPattern;string userPattern;int userScore;int i; userScore = 0; cin >> simonPattern;cin >> userPattern; /* Your solution goes here */ cout << "userScore: " << userScore << endl; return 0;} Please help me with this problem using c++.
Write a while loop that prints userNum divided by 4 (integer division) until reaching 2 or less. Follow each number by a space. Example output for userNum = 160:40 10 2
Write a loop that reads positive integers from standard input and that terminates when it reads an integer that is not positive. After the loop terminates, it prints out the sum of all the even integers read, the sum of all the odd integers read, a count of the number of even integers read, and a count of the number of odd integers read, all separated by exactly one space. Declare any variables that are needed.
Output integer's digits Given an input positive integer, output each digit on its own line, starting with the rightmost digit. Ex: If the input is 935, the output is: 5 3 9 Hints: Use the mod operator (%) to get the rightmost digit. Mod by 10 to get the rightmost digit. Use a loop that keeps a current dividend (the number being divided). In each iteration, output the rightmost digit, then update the divisor by dividing by 10. End the loop when the divisor is 0. in java
On a piano, a key has a frequency, say f0. Each higher key (black or white) has a frequency of f0 * rn, where n is the distance (number of keys) from that key, and r is 2(1/12). Given an initial key frequency, output that frequency and the next 4 higher key frequencies. NOTE: You must use a for loop. Output each floating-point value with two digits after the decimal point, which can be achieved by executingcout << fixed << setprecision(2); once before all other cout statements. Ex: If the input is: 440.0 (which is the A key near the middle of a piano keyboard), the output is: 440.00 466.16 493.88 523.25 554.37 Note: Use one statement to compute r = 2(1/12) using the pow function (remember to include the cmath library). Then use that r in subsequent statements that use the formula fn = f0 * rn with n being 1, 2, 3, and finally 4. Note: setprecision requires you to include the iomanip header file Write in C++.Please and thank you.
Write a loop that reads positive integers from standard input and that terminates when it reads an integer that is not positive. After the loop terminates, it prints out the sum of all the even integers read and the sum of all the odd integers read(The two sums are separated by a space). Declare any variables that are needed.
a and b are int variables containing values, and a < b.Write a for loop that prints all odd numbers from a to b (both inclusive).(Example: if a=25, b=82, then it will print 25 27 29 .... 79 81)Write only the for loop with its block, nothing else. with java
Given positive integer numInsects, write a while loop that prints that number doubled without reaching 200. Follow each number with a space. After the loop, print a newline. Ex: If numInsects = 16, print:16 32 64 128 C++ #include <iostream>using namespace std; int main() { int numInsects; cin >> numInsects; // Must be >= 1 /* Your solution goes here */ return 0;}