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- Let z^1 = 4 (cos 7π/12+ i sin 7π/12) and z^2 = 2 (cos 5π/12+ i sin 5π/12) Find z1z Find z1/z2Prove that 1.) 1+sec^2\theta \sin ^2\theta =\sec ^2\theta 2.) \frac{sin\theta }{1-cos\theta }+\frac{1-cos\theta }{sin\theta }=2csc\theta 3.)1+\frac{1}{sin\theta }=\frac{tan^2\theta }{sec\theta -1} 4.) \frac{1}{sec^2\theta }+\frac{1}{csc^2\theta }=1 5.) \frac{1+sin\theta }{sin\theta }=\frac{cot^2\theta }{csc\theta -1} 6.) cos^2\theta +\sin ^2\theta \cos ^2\theta =1When r^2 = x^2 + y^2, we have x = rcos theta and y = rsin theta, and When r^2 = y^2 + z^2, we have y = rcos theta and z = rsin theta. ... So, does this imply that when r^2 = x^2 + z^2, that x = rcos theta and z = rsin theta, or x = rsin theta and z = rcos theta, or how to we distinguish which is cos theta and which is sin theta?