sin2z+721任22 4. lim よー2 z (2十1)

Q: 4 ex lim X 4 + 3e*

A: Given,              limx→∞4-ex4+3ex

Q: Verify the identity tanh2 x + sech2 x = 1

A:

Q: Determine la solución general de la ecuación diferencial Y'-2x/2-x^2(y)=e^x. Y(2)=4

A:

Q: tan(2e) lim 30 Costue)

A: Solution is given below:

Q: Find the limits

A: Recall

Q: Compute Lim メーフ4 7x+5 -3 Sin ? X 2)x-70 3X イメ2+2 3) -00 X-7-00 2x-1

A: (1)Consider the given function with limit:

Q: tan x ....+ C sec x Select one: 3(sec5/3x) 3 5 sec x 3(sec5/3x) 3 V sec x 2(sec1:5x) +2y sec x 3 O…

A: Use substitution method to solve this

Q: tan(5x) 2. lim 3x

A:

Q: lim (х — Vx? + х

A: Consider fx=x-x2+x. Simplify the above function. fx=x-x2+xx+x2+xx+x2+x=x2-x2-xx+x2+x=-xx+x2+x

Q: Limit メ+5 メ→-5 |Jx-っ-4

A: To findlimx→-5x+5|x2-9|-4

Q: tan (2x) 3. 24. lim- %3D .3

A: We replace tan(2x) by sin(2x)cos(2x)…

Q: tan(2 – j5) j(2-j5) +7- jv2 In(-5)| (3220° – sin 20 + jln5)*|

A:

Q: tan 9x - tan 5x 11. Simplify 1+ tan 9xtan 5x (SHOW WORK)

A: follow next step

Q: 1) lim (1- – - 3,

A: The given limit is limx→∞1-3xx

Q: lim (4+ (2? + y°) In(x² + y²)) (1,y)(0,0)

A: Given; lim(x,y)=(0,0)[4+(x2+y2)ln(x2+y2)]

Q: tan(1 – x) limx→1 2 2x +x – 3,

A: Limit

Q: 5) 증-글(cosy)x 2

A: 5)dxdy-x2y=-12cos yx3Bernoulli equation1x3dxdy-12x2y=-12cosy--(1)let 1x2=tdifferentiating both side…

Q: tan(x) Q1: limx¬n X-n is

A:

Q: So sin() -=? lim, o

A: Given that:limx→0+∫0xsin(t2)dtx3

Q: lim 19th 3. 1/-

A:

Q: Graphing a Trigonometric Function In Exercises39–48, use a graphing utility to graph the…

A: Hello. Since your question has multiple parts, we will solve first question for you. If you want…

Q: 5. Evaluate: sec°0 tan’0 de

A: Consider the given integral. I=∫sec9θtan7θdθ Further, simplify.…

Q: . What is lim tan(x)? Why? 2 AY 10 8 6 4 2 -1A -0.5 0.5T, 1.57 27 2.57, 37 -4 -6

A: 1) limx→π2+tan(x)=? 2) limx→0+f(x) =? and limx→0-f(x) =?

Q: (B) Evaluate | tan (7x +1) sec³(7x +1) dr.

A: We will use simple integration rules to solve this question.

Q: 11) Verify the identity: sec 2x-1 sec' x-1= sec 2x +1

A: We start with the right side

Q: lim (In(3x + 1) – In(2x + 1))

A: To evaluate the below limit

Q: 5. 4 f sin + 2zdz

A:

Q: tan(2 – j5) j(2-j5) +7- jv2 In(-5) (320° – sin 20 + jln5)*

A:

Q: 7) 2tan² 0 = 1 + 2tan 0 + 3tan² 0 8) 1= tan² 0 + sec 0

A:

Q: Evaluate: / sec (5x + 1).5dx Select one: O cor(5x+1) + c O tan(5x + 1) + c O cor(5x) + c O tan(5x) +…

A: Use the substitution method and simplify the given integration than integrate.

Q: 2-limyo(x.secx.cscx)

A:

Q: What is the lim (3)¯ I 7 sec (7x) cos(3x)?

A:

Q: 19. lim x→2- x² – 4 eas y + 6 21. lim y→6+ y2 – 36 -

A: Given that limx→2- xx2-4 limx→6+y+6y2-36

Q: Evaluate /5 sec(8 x)dx In(tan(8 x)+sec(8 x)|) + c 8. 5 In(|tan(8 x)+sec(8 x)|) + c 8. 05 In(|tan(8…

A: By using proper substitution and formula integral can be easily solved.

Q: sin (tan' 8, zan-)= 0.35 O -0.35 O 0.40 O -0.40 O O O

A: Inverse Trigonometric ratios are just the opposite of Trigonometric ratios as Trigonometric ratios…

Q: /14-х-3 lim 1-V6-х X→5 4-Vx lim х>16 16-х

A:

Q: 1. lim ux-121 X-3

A:

Q: 4+ 5x = sin (ry")

A:

Q: lim xi-

A:

Q: Find the limit

A: Given

Q: 2sin2 x-3sinx+1=0

A: It is a quadratic equation of sin x. So we solve it by factorising.

Q: 2+ sec (3x) (c) lim x→7/6 tan (3x) 1

A:

Q: lim Vz+6-V6

A:

Q: 22 xtan"x secx

A:

Q: Prove that

A:

Q: 2+ sec (3x) (с) lim я (6 tan (3x) —1

A:

Q: O Lim tanx メーや メ O Lim 2 5+. 6 3) Lim y4 3-→ yリデッチァメネ9

A: As per guideline we have to solve only 3 subparts