tan 0 - 1 lim 8/4 4

Q: 2 (х —1) lim 3 X 00 х+2

A:

Q: 4. lim(5 )(-10x ) 5. lim(13x – 2)( x + 1 )

A: Given: L1=limx→155-10x, L2=limx→713x-2x+1 We know that limx→afxgx=limx→afxlimx→agx…

Q: tan 2x 9. lim 2x

A: Explanation of the answer is as follows

Q: 1. lim 2x

A:

Q: tan(4 x) lim x>0

A:

Q: 1 lim x→2- x – 2

A: The notation indicates that the limit is the value the function approaches to from the left of the…

Q: lim et- ハ→0 ¥

A:

Q: 111. lim cos x -2

A: To find,

Q: tan(23z) lim

A: This problem of limit can be solved by the L' Hospital rule which is explained in step 2.

Q: tan(5x) 2. lim 3x

A:

Q: whatin Lim (19x) tan(3x メ→0 2.

A: The limit is limx→0+9x tan3x+π2. Factor out the constant term.  limx→ 0+9xtan3x+π2=9·limx→…

Q: x+5 lim x→2 x´ – 4 x+5 lim x→2* x? – 4 x+5 lim 2 x→2 x² - 4

A: The given limits,limx→2-x+5x2-4limx→2+x+5x2-4limx→2x+5x2-4

Q: Find the limit

A:

Q: 2 In (1+ lim X -00 3 tan 2 x

A:

Q: Evaluate (i) lim (1 – tan 6) sec 0

A:

Q: 22- iz lim 23 +1 10 -1 0 20 00

A:

Q: tan2x 4) lim, -X, 2 x- 2

A: Explanation of the answer is as follows

Q: tan(14x) lim x→0 5x |

A:

Q: 5. Evaluate lim sin(x)– (x² + 3x – e*). (x³ – 2x2 - 6 + 3x) 6. Evaluate lim X→2 х - 2

A:

Q: lim In(x+3) 4) 1

A: Evaluate :     limx→∞ln3xlnx+3

Q: 1.1) lim 1-у2х+1 1+ →-

A:

Q: tan (5x) lim x0

A:

Q: 1 Evaluate lim 1 sin

A: The given limit is limx→∞1sin1x Let x=1/z z=1/x when x tends to infinity z tends to 0

Q: 1. 2. 3. () ) lim lim 2 tan lim (x²–16) x+2 - x →4 4-x х -3 х-2

A: Note : According to our answering guidelines we have to solve only 3 sub parts (if multiple subparts…

Q: 1) lim x100+500 ex

A: As per our guidelines we can answer only 1 question so kindly repost the remaining questions…

Q: 1) lim X-2 2x-4n x(1-cosx) 2) lim х-0 tan(tan?x)

A:

Q: 1. lim + 2 = 3 X00 x

A: Question number 1,Given,           limx→∞x2x+2=3

Q: 0.Lim ュー)×40,2 メ-2 メ→o “波 (1+x) - 1 4)Lim *キX メーフ。

A: In this question , we can find the limit .

Q: lim (1+ tan 3x)*

A:

Q: 1.2) lim 1-/2г+1 x→0

A: Follow next step

Q: Calculate the limit

A: limx→∞ arctanx2+99-xApplying Chain rule: =-π2limx→∞ arctanx2+99-x=-π2  Decimal:   -1.57079…

Q: 1 11. lim -1- |x +1 (x+ 1)2 + 3]

A:

Q: tan 3x Find lim x0 tan 2x

A: We have to evaluate the following limit: limx→0tan3xtan2x

Q: ズー1 2. lim X-3 エ+1

A: Consider the provided expression, limx→3x-1x+1 Evaluate the above limit.

Q: tan3x lim 20 In(1+ x)

A: limx→ 0tan3xln1+xApplying L'Hopital rule=limx→ 0sec23x· 311+xPut x=0=sec23· 0· 311+0=3

Q: 2) lim (x – 1)tan- 2

A:

Q: 1. lim+4 = 5 X00 X

A: From the given problem:   limx→∞x5x+4=5   L.H.S.=limx→∞x5x+4   As we know that…

Q: 35. lim (sec 2/2 x – tan æ)

A:

Q: Find the limit

A:

Q: [3sin(θ)*cos(θ) - θ]/ [tan(θ) - θ]   lim θ -> 0

A: Let  f (θ) = [3sin(θ)*cos(θ) – θ] / [tan(θ) – θ].Find the limit of the function as θ approaches 0.

Q: 1 27. lim x→2+ |2 – x|

A:

Q: find lim x-> 0, cos (12x)-1 / 3x

A: Given,              limx→0cos 12x - 13x Move the term 1/3 outside of the limit because it is…

Q: 1. Find lim an 3(x+h)-tan 3x A. 3 sec 3x tan 3x B. sec? 3x C. 3 tan 3x D. 3 sec2 3x

A: limh→0 tan3x+h-tan3xh So here fx =tan(3x) Now we need to find derivative of fx with respect to x…

Q: 9. 4. lim X-3 x2 - 9

A: Since you have asked multiple question, as per our guidelines we are supposed to answer only one…

Q: Example 8 Prove that sin x lim = 0. X00

A: We have given a question they're asking for how do we evaluate limit for sine x over x when x…

Q: x² +9 lim tan 9 - x

A:

Q: 44. lim sin² x 7/4

A: The limit is, 1/2 The detailed solution is as follows below :

Q: nt2 2– 1) tan L = lim 2 t-1

A:

Q: 19.) lim X+2 X+-2 X ³³+8 3 tiran

A: To find limit of the given function as x approaches to -2.

Q: tan(4x) lim x-→0 tan(5x)

A:

Q: 1 ex-1. lim 1 ex+1

A:

Q: 1 lim(x²-3x+1) 3. lim tan(x²) 7. lim 2²-1-2 x²-4

A: Since you have posted multiple question in this question which are not interlinked so i have solved…

Q: 2+ sec (3x) (с) lim я (6 tan (3x) —1

A:

Q: lim lx-1| х>1 1-х ?

A:

Q: Sec(0)xtan (20) lim 30

A:

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.