sin(4x) 8. Compute lim x-0 tan(3x)

Q: 5. Evaluate lim sin(x)-(x² +3x– e*). 1-0

A:

Q: x(cos(x) – 1), x0 sin(x) – x Evaluate: lim-

A: It is given that,  limx→0xcosx-1sinx-x We have to evaluate it.

Q: 1-cos x lim sin x x→0

A: Given: limx→01-cosxsinx

Q: lim (cos(9x)) (+) +0+x

A:

Q: 2) lim (x – T)tan5

A:

Q: lim x-->0 (sin(2x^3))/(3x^2)

A:

Q: (2) 1: limx-1 sin(x3–1) x-1

A: limx→1 (2-1x)2sin(x3-1)x-1=limx→1 (2x-1x)2sin(x3-1)x-1=limx→1 4x2-4x+1x2sin(x3-1)x-1=limx→1…

Q: 1+3x- cOs x 2.) lim tan x

A: In this question we need to find limit of the given function.

Q: 2Tan 'x -x 9. lim, 2x – Sin^x

A:

Q: エ→2 x² -4 1- cos 2x 7) lim X sin x エ→0

A: Since you have asked multiple question, we will solve the first question for you as per our guide…

Q: 2x -cos(2x)- 2x - (b) lim | x2

A:

Q: 2 cos x tan 7x 2b) find lim

A:

Q: 2 2- limx-1 sin(x3-1) x-1

A:

Q: tan 3x 18. lim 1-cos x 19. lim -0 tanx

A:

Q: sin(x²) x→0 In(cosx) 4. Evaluate lim

A:

Q: x-sin x' A- Find limx-0 1-cos x.

A: We will apply the L'hospitals rule because the limit is of 0/0 form.

Q: sin°(,² – 4) (x+2) tan(x+ 2 limy→-2

A: We have to solve

Q: (c) (d) sin 3x lim z0 tan 3r lim (In(sin 2x) - In(tanz)) +0+z

A: Here we have to solve the given limits.

Q: (1) limx¬(1/2)-(tan x)cos x

A: Given that  1)limx→(π2)-(tanx)cosx 2)limx→0x-3(tan-1x-x)

Q: tan (3x) lim x→0 sin (2x)

A: Given query is to find the limit of the expression.

Q: lim a sin(1/2),

A: Given,           limx→0xsin1x

Q: x + sin 2x lim x-2 x – sin 2x О з O 2 O 1/3 О 12 O other:

A:

Q: (1) lim,o In (sec x) 3x (2) lim, (tan x)*

A:

Q: 3. Find lim x sin II

A: Given limx→∞xsin(πx)

Q: lim sin(1/r),

A: We have to find limit

Q: 2 sin x 1 lim is

A:

Q: 3 lim z? sin(-

A:

Q: 1-sinx x²-49 b. lim x→7 x-7 lim C. lim X→00 x²+1 a. X 1-cosx

A:

Q: 4-V16+h 9. lim x+sin x 12. lim

A: Note: As per bartleby guidelines for more than one questions asked only one question is to be…

Q: 4x 3-limx-0 tan5x sin(cos y) 4-lim, y- 2

A:

Q: 7- sin-(e*) 2 lim V1 - e2x

A:

Q: (2-4* limx-1 sin(x³–1) X. x-1

A:

Q: lim (4x+cosx) / x ? x--->infinity

A:

Q: 3 lim tan³ 2x x→0

A:

Q: lim as x approaches 0   x sin(x)/1-cos(x)

A:

Q: 1-cos (x-T) lim x→T(x-T)sin (x-π)

A: Given limit, limx→π1-cosx-πx-πsinx-π

Q: 1f. lim (tanx)x x->0+

A: Given,

Q: cos(x)-1 lim-0 sin(x) limx-0 %3D = 1

A: Substituting x=0 in cosx-1xwill result in indeterminate form 00. Use L'Hospital's rule,…

Q: 2 sin x-sin 2x lim х-sin x 3 O -3 6 -6 о O O

A: Given- limx→02sinx-sin2xx-sinx To Find- The valuie of the limit.

Q: et Lim x-0 +e³-x²-2 sin² x-x²

A:

Q: 8 sin((k – 1)x) sin (2x) П ¤(ekz – 1) lim \k=2

A:

Q: V+12-4 3 .lim X-2 tan3x 2. lim X-0 sinax 4). lim X00 x-7x+1 x-2

A:

Q: х(4+sin 6x) 3. lim X→+0 х+1

A:

Q: (1- cos.x)? cosx) limx-0 x sin(x2)

A:

Q: 1-cos(x) lim x→0

A:

Q: limx¬1 x(1 – cos-) x→1

A:

Q: Evaluate

A: Our Aim is to evaluate the limit given below:-limx→0tan (2x)x-(i)