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Since f'(c) f(1) – (0) f(1) – f(0) = 1, f(c) = 1. We therefore equate f'(x) to 1 and solve for x. and %3! %3D 1-0 1-0 f'(x) = 1 4-1/5 = 1 x-1/5 4. Raise both sides of the equation to the fifth power and simplify. 15.

Since f'(c) f(1) – (0) f(1) – f(0) = 1, f(c) = 1. We therefore equate f'(x) to 1 and solve for x. and %3! %3D 1-0 1-0 f'(x) = 1 4-1/5 = 1 x-1/5 4. Raise both sides of the equation to the fifth power and simplify. 15.

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
Chapter2: Graphical And Tabular Analysis
Section2.1: Tables And Trends
Problem 1TU: If a coffee filter is dropped, its velocity after t seconds is given by v(t)=4(10.0003t) feet per...
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Since f'(c) f(1) – (0) (1) - f(0) = 1, f(c) = 1. We therefore equate f'(x) to 1 and solve for x. and %3D %3D 1-0 1-0 f'(x) = 1 4-1/5 = 1 x-1/5 4. Raise both sides of the equation to the fifth power and simplify.
Transcribed Image Text:Since f'(c) f(1) – (0) (1) - f(0) = 1, f(c) = 1. We therefore equate f'(x) to 1 and solve for x. and %3D %3D 1-0 1-0 f'(x) = 1 4-1/5 = 1 x-1/5 4. Raise both sides of the equation to the fifth power and simplify.
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