Since the matrices are linearly dependent we must now express one of the matrices as a linear combination of the others. We first recall the given set of matrices. 0 2 D = -1 1 3 0 -1 B = 2. C = 1 -з 1 -2 Next, recall the previously created matrix equation and substitute the variables A, B, C, and D in place of the matrices. -1 1 3 0 + c, + Ca -3 1 -1 0 + C. -1 = 0 7 -2 2 CA + czB + c3C + cD = 0 Finally, substitute c, = -4t, c, = -t, c, = 2t, and c, = t into the matrix equation. %3! %3D CA + c„B + c3C + cD = 0 ):)A + (-t)8 + (( De)c + (t)D = 0

College Algebra (MindTap Course List)
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Chapter6: Linear Systems
Section6.3: Matrix Algebra
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Since the matrices are linearly dependent we must now express one of the matrices as a linear combination of
the others.
We first recall the given set of matrices.
-1 1
3 0
0 2
D =
B =
2.
C =
1
-з 1
-2
Next, recall the previously created matrix equation and substitute the variables A, B, C, and D in place of the
matrices.
-1 1
3 0
+ C,
+ Ca
-3 1
-1 0
+C.
-1
= 0
7
-2 2
CA + czB + c3C + cD = 0
Finally, substitute c, = -4t, c, = -t, c, = 2t, and c, = t into the matrix equation.
%3D
CA + c„B + c3C + cD = 0
De)c + (t)D = 0
)e)A + (-t)8 + ((
Transcribed Image Text:Since the matrices are linearly dependent we must now express one of the matrices as a linear combination of the others. We first recall the given set of matrices. -1 1 3 0 0 2 D = B = 2. C = 1 -з 1 -2 Next, recall the previously created matrix equation and substitute the variables A, B, C, and D in place of the matrices. -1 1 3 0 + C, + Ca -3 1 -1 0 +C. -1 = 0 7 -2 2 CA + czB + c3C + cD = 0 Finally, substitute c, = -4t, c, = -t, c, = 2t, and c, = t into the matrix equation. %3D CA + c„B + c3C + cD = 0 De)c + (t)D = 0 )e)A + (-t)8 + ((
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